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ExtremeBDS [4]
3 years ago
10

How many grams of P4O10 would be produced when 0.700 mole of phosphorus is burned?

Chemistry
1 answer:
AysviL [449]3 years ago
8 0
We can solve the equation and show the solution below:

Oxygen atomic number is 16.
Phosphorus atomic number is 32.

We have the molecular weight:
Molecular weight = (31*4) + (16*10)
Molecular weight = 284 grams/mol

Solving for the grams:

0.4 mole (for P4) * (1 mol P4O10/1 mol P4) * (284 grams P4O10/1 mole P4O10)
Total grams = 113.6

The answer is 113.6 grams.
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iragen [17]

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0+10+16+22+27=75/5=15 cm^3

then, 15/30= 0.5 cm^3/s(average rate of rxn)

2. 0+15+30+45+60+75+90+105+120=540/9=60 s

0+10+16+22+27+31.50+36+39.5+42=224/9=24.89cm^3

then, 24.89/60=0.414cm^3/s (avrg rate of rxn)

3. overall rxn add all the time divide by 12 and the volume add them too and divide by 12. after take average volume divide by the average time to get the average rate of overall rxn

4. 16/30= 0.533cm^3/s

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3 0
3 years ago
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Oksanka [162]

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Molarity of 40 ml of NaoH is 0.3125 mL

Explanation:

As we know  

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Substituting the given values, we get  

0.5 * 25 = X* 40 \\X = \frac{0.5*25}{40} \\X = 0.3125

Molarity of 40 ml of NaoH is 0.3125 mL

6 0
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chubhunter [2.5K]

The main idea was that the best thing for the American people to do was to fight for their independence from Great Britain.

8 0
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