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Irina18 [472]
2 years ago
11

It’s busy at the bakery counter , and a loyal customer / member stops you to charge as he talking , you notice another customer

never newrby who needs help
Engineering
1 answer:
allsm [11]2 years ago
6 0

The Most likely scenario is to: Tell him that you will be happy to continue talking with him right after you help the other customer or the member.

The Least likely is to: Interrupt to ask if there is anything you can help him with today.

<h3>What is a likely scenario?</h3>

The scenario is known to be one when a person  talk about a likely or possible event that can take place.

Here, the person is talking about the way in which an event can or may develop.

Note therefore, based on the above, The Most likely scenario is to: Tell him that you will be happy to continue talking with him right after you help the other customer or the member. While the Least likely is to: Interrupt to ask if there is anything you can help him with today.

Learn more about Most likely scenario from

brainly.com/question/24141565

#SPJ1

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Refrigerant-134a enters an adiabatic compressor as saturated vapor at -24°C and leaves at 0.8 MPa and 60°C. The mass flow rate o
Leni [432]

Answer:

(a) The power input to the compressor: \dot{W}=73.07 kJ/s = 73.07 kW

(b) The volume flow rate of the refrigerant at the compressor inlet: \dot{v}=0.209 m^{3}/s

Explanation:

(a)

We need to check the values of enthalpy (as we have an open system) for both states, being the inlet, state 1 and the outlet, state 2. We will know these values by checking the vapor charts of R134a, I used the ones found in Thermodynamics of Cengel, 7th edition.

Then, our values are:

h_{1}=235.92kJ/kg\\h_{2}=296.81kJkg

Now we proceed to know the work with the following expression:

\dot{W}=\dot{m}(h_{2}-h_{1})

Now we replace values and our result is:

\dot{W}=73.07 kJ/s = 73.07 kW

(b)

To know the volume rate at the compressor inlet, we need to know the specific volume in that phase, as we have that is saturated and at -24°C, we can read our table:

\nu=0.1739m^{3}/kg

With our specific volume and the mass rate, we can calculate the volume rate:

\dot{v}=\nu * \dot{m}\\\dot{v}=0.209 m^{3}/s

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Explanation:

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