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Irina18 [472]
1 year ago
11

It’s busy at the bakery counter , and a loyal customer / member stops you to charge as he talking , you notice another customer

never newrby who needs help
Engineering
1 answer:
allsm [11]1 year ago
6 0

The Most likely scenario is to: Tell him that you will be happy to continue talking with him right after you help the other customer or the member.

The Least likely is to: Interrupt to ask if there is anything you can help him with today.

<h3>What is a likely scenario?</h3>

The scenario is known to be one when a person  talk about a likely or possible event that can take place.

Here, the person is talking about the way in which an event can or may develop.

Note therefore, based on the above, The Most likely scenario is to: Tell him that you will be happy to continue talking with him right after you help the other customer or the member. While the Least likely is to: Interrupt to ask if there is anything you can help him with today.

Learn more about Most likely scenario from

brainly.com/question/24141565

#SPJ1

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A 0.40-m3 insulated piston-cylinder device initially contains 1.3 kg of air at 30°C. At this state, the piston is free to move.
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Answer:

(a) The Final Temperature is 315.25 K.

(b) The amount of mass that has entered  0.5742 Kg.

(c) The work done is 56.52 kJ.

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Explanation is in the following attachments.

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3 years ago
Refrigerant 134a enters the evaporator of a refrigeration system operating at steady state at -16oC and a quality of 20% at a ve
Dmitry [639]

Answer:

mass flow rate = 0.0534 kg/sec

velocity at exit = 29.34 m/sec

Explanation:

From the information given:

Inlet:

Temperature T_1 = -16^0\ C

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Outlet:

Temperature T_2 = -16^0 C

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The following data were obtained at saturation properties of R134a at the temperature of -16° C

v_f= 0.7428 \times 10^{-3} \ m^3/kg \\ \\  v_g = 0.1247 \ m^3 /kg

v_1 = v_f + x_1 ( vg - ( v_f)) \\ \\ v_1 = 0.7428 \times 10^{-3} + 0.2 (0.1247 -(0.7428 \times 10^{-3})) \\ \\  v_1 = 0.0255 \ m^3/kg \\ \\ \\  v_2 = v_g = 0.1247 \ m^3/kg

m = \rho_1A_1v_1 = \rho_2A_2v_2 \\ \\  m = \dfrac{1}{0.0255} \times \dfrac{\pi}{4}\times (1.7 \times 10^{-2})^2\times 6  \\ \\ \mathbf{m = 0.0534 \ kg/sec}

\rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ A_1 =A_2  \\ \\  \rho_1v_1 = \rho_2v_2   \\ \\ \implies \dfrac{1}{0.0255} \times6 = \dfrac{1}{0.1247}\times (v_2)\\ \\ \\\mathbf{\\ v_2 = 29.34 \ m/sec}

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3 years ago
What type of engineering do you think would help solve this SDG???
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Answer:

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