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timofeeve [1]
3 years ago
10

A gas contained in a piston cylinder assembly undergoes a process from state 1 to state 2 defined by the following relationship

and given properties. Determine the final volume (V2) of the gas. P*V= constant P1 = 445 kPa V1 = 2.6 m^3 P2 = 140 kPa ans is 8.3 but how do i get it?
Engineering
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

V2 = final volume = 8.3m^3

Explanation:

Given P1 = 445 kPa, V1 = 2.6 m^3, P2 = 140 kPa

From PV = constant; P1V1 =P2V2 , where V2 = final volume

V2 = P1V1/P2

Substituting in the equation ;

V2 = 445 x 2.6 / 140

V2 = final volume = 8.3m^3

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___________ is NOT a common injury that an automotive tech may experience at work.
Degger [83]

Answer:The most common injuries were sprains/strains (39% of the total), lacerations (22%), and contusions (15%). Forty-nine percent of the injuries resulted in one or more lost or restricted workdays; 25% resulted in 7 or more lost or restricted workdays.

Explanation:

The most common injuries were sprains/strains (39% of the total), lacerations (22%), and contusions (15%). Forty-nine percent of the injuries resulted in one or more lost or restricted workdays; 25% resulted in 7 or more lost or restricted workdays.

7 0
3 years ago
Ammonia is one of the chemical constituents of industrial waste that must be removed in a treatment plant before the waste can s
Yanka [14]

Answer:

Following is attached the solution or the question given.

I hope it will help you a lot!

Explanation:

5 0
3 years ago
Match each term in the second column with its correct definition in the first column.
Levart [38]

Answer:

The filled in the black answers is:

1. work book

2. Spreadsheet

3. Cell

4. Sheet tabs

5. Column

6. Row

7.Cell content

8. data

9. Formula

10. Constant value

11. Number value

12. Cell address

7 0
3 years ago
Base course aggregate has a target density of 121.8 lb/ft3 in place It will be laid down and compacted in a rectangular street r
irakobra [83]

Answer:

total weight of the aggregate = 3594878.28 lbs

Explanation:

given data

density = 121.8 lb/ft³

area =  1000 ft x 60 ft x 6 in = 1000 ft x 60 ft x 0.5 ft

moisture = 3.5 %

compaction = 95%

solution

we get here first volume of the space that is filled with the aggregate that is

volume = 1000 ft x 60 ft x 0.5 ft  = 30,000 cu ft

now we get fill space with aggregate that compact to 95% of dry density.

so we fill space with aggregate of density that is = 95% of 121.8

= 115.71 lb/ cu ft

so now dry weight of aggregate is

dry weight of aggregate = 30,000  × 115.71 = 3471300 lb

when we assume that moisture percentage is by weight

then weight of the moisture in aggregate will be

weight of the moisture in aggregate = 3.56 % of 3471300 lb  

weight of the moisture in aggregate = 123578.28 lbs

and

we get total weight of the aggregate to fill space that is

total weight of the aggregate = 3471300 lb +123578.28 lb

total weight of the aggregate = 3594878.28 lbs

4 0
3 years ago
When working cattle through a chute, stop cattle by moving…point of balance.
timofeeve [1]

When the handler has reached the point of balance of the animal, they should stop walking so that they may move only one animal at a time. The point of balance for cattle that are being worked with in limited places such as races and chutes is often found at the animal's shoulder, as seen by the diagrams.

This is further explained below.

<h3>What is a chute?</h3>

Generally, Chutes are channels, planes, or passageways that are either vertical or slanted and through which things may be transported using only gravity.

In conclusion, When the handler has reached the point where the animal's point of balance has been crossed, they should stop walking so that they may move just one animal.

As seen in the illustrations, the point of balance for cattle being worked with in restricted spaces like races and chutes is often located at the animal's shoulder.

Read more about chute

brainly.com/question/10976905

#SPJ1

3 0
2 years ago
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