The equation of the line through (3,-5) and perpendicular to -3x + 2y = 12 in slope-intercept form is y = -2/3x + 1
<h3>Equation of a line</h3>
The equation of a line is expressed as;
y = mx + b
m is the slope
b is the y-intercept
Given the equation -3x + 2y = 12
2y = 3x + 12
y = 3/2x + 6
From the equation, the slope that is perpendicular to the slope is -2/3
<u>Determine the equation</u>
y-(-5) = -2/3(x-3)
y+5 = -2/3x + 6
y = -2/3x + 6 - 5
y = -2/3x + 1
Hence the equation of the line through (3,-5) and perpendicular to -3x + 2y = 12 in slope-intercept form is y = -2/3x + 1
Learn more on equation of a line here: brainly.com/question/13763238
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