Question

Write the equation of the line through (3,-5) and perpendicular to -3x + 2y = 12 in slope-intercept form.

Answer 1

The equation of the line through (3,-5) and perpendicular to -3x + 2y = 12 in slope-intercept form is y =  -2/3x + 1

Equation of a line

The equation of a line is expressed as;

y = mx + b

m is the slope

b is the y-intercept

Given the equation -3x + 2y = 12

2y = 3x + 12

y = 3/2x + 6

From the equation, the slope that is perpendicular to the slope is -2/3

Determine the equation

y-(-5) = -2/3(x-3)

y+5 = -2/3x + 6

y =  -2/3x + 6 - 5

y =  -2/3x + 1

Hence the equation of the line through (3,-5) and perpendicular to -3x + 2y = 12 in slope-intercept form is y =  -2/3x + 1

Learn more on equation of a line here: brainly.com/question/13763238

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