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3 years ago

Match the inequality to the graph of the solution C - 6 < 4

Mathematics

1 answer:

SVEN [57.7K]3 years ago

4 0

Answer:

Step-by-step explanation:

C - 6 < 4

C < 10

Open circle at 10 and shade to the left.

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In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 3.0 m/s up a 22.0° inclined track

Aloiza [94]

Answer:

Approximately $0.31\; \rm m$ , assuming that $g = 9.81\; \rm N \cdot kg^{-1}$ .

Step-by-step explanation:

Initial kinetic energy of the sled and its passenger:

$\begin{aligned}\text{KE} &= \frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2} \times 14\; \rm kg \times (3.0\; \rm m\cdot s^{-1})^{2} \\ &= 63\; \rm J\end{aligned}$ .

Weight of the slide:

$\begin{aligned}W &= m \cdot g \\ &= 14\; \rm kg \times 9.81\; \rm N \cdot kg^{-1} \\ &\approx 137\; \rm N\end{aligned}$ .

Normal force between the sled and the slope:

$\begin{aligned}F_{\rm N} &= W\cdot \cos(22^{\circ}) \\ &\approx 137\; \rm N \times \cos(22^{\circ}) \\ &\approx 127\; \rm N\end{aligned}$ .

Calculate the kinetic friction between the sled and the slope:

$\begin{aligned} f &= \mu_{k} \cdot F_{\rm N} \\ &\approx 0.20\times 127\; \rm N \\ &\approx 25.5\; \rm N\end{aligned}$ .

Assume that the sled and its passenger has reached a height of $h$ meters relative to the base of the slope.

Gain in gravitational potential energy:

$\begin{aligned}\text{GPE} &= m \cdot g \cdot (h\; {\rm m}) \\ &\approx 14\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times h\; {\rm m} \\ & \approx (137\, h)\; {\rm J} \end{aligned}$ .

Distance travelled along the slope:

$\begin{aligned}x &= \frac{h}{\sin(22^{\circ})} \\ &\approx \frac{h\; \rm m}{0.375}\end{aligned}$ .

The energy lost to friction (same as the opposite of the amount of work that friction did on this sled) would be:

$\begin{aligned} & - (-x)\, f \\ = \; & x \cdot f \\ \approx \; & \frac{h\; {\rm m}}{0.375}\times 25.5\; {\rm N} \\ \approx\; & (68.1\, h)\; {\rm J}\end{aligned}$ .

In other words, the sled and its passenger would have lost (approximately) $((137 + 68.1)\, h)\; {\rm J}$ of energy when it is at a height of $h\; {\rm m}$ .

The initial amount of energy that the sled and its passenger possessed was $\text{KE} = 63\; {\rm J}$ . All that much energy would have been converted when the sled is at its maximum height. Therefore, when $h\; {\rm m}$ is the maximum height of the sled, the following equation would hold.

$((137 + 68.1)\, h)\; {\rm J} = 63\; {\rm J}$ .

Solve for $h$ :

$(137 + 68.1)\, h = 63$ .

$\begin{aligned} h &= \frac{63}{137 + 68.1} \approx 0.31\; \rm m\end{aligned}$ .

Therefore, the maximum height that this sled would reach would be approximately $0.31\; \rm m$ .

7 0

3 years ago

At a restaurant, you order a meal that costs $8. you leave a 15% tip. the sales tax is 6%. what is the total cost of the meal?

Oksi-84 [34.3K]

Easy! multiply the 6% by $8 then add it to the $8, now, multiply the 15% by the total of the cost with tax. then you all that to the total. ($9.75)

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3 years ago

Find the value of x. Round to the nearest degree as needed.

Bas_tet [7]

9514 1404 393

Answer:

x° = 29°

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relevant trig relationships. Here, you have the hypotenuse and the side opposite the unknown angle. So, the appropriate relation is ...

Sin = Opposite/Hypotenuse

sin(x°) = 12/25

x° = arcsin(12/25) ≈ 28.69°

The value of x is about 29.

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3 years ago

You need to buy 5 notebooks for your classes at school. Each notebook costs $2.79. What is the total costs of 5 notebooks Before

aev [14]

multiply 2.79 x 5

2.79*5 = 13.95 before tax

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3 years ago

Reggie Jackson played in major league baseball for 21 years.although this slugger was known best for his home runs,he holds the.

lutik1710 [3]

Find the unit rate
do 2597÷21

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3 years ago

Match the inequality to the graph of the solution C - 6 < 4​

Match the inequality to the graph of the solution C - 6 < 4