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LekaFEV [45]
2 years ago
15

What mass of ag2co3 could you produce from 12.7 g agno3 assuming that it is the limiting reagent?

Chemistry
1 answer:
zhenek [66]2 years ago
7 0

10.3 g of  Ag_{2} CO_{3} will produce from 12.7 g AgNO_{3}.

In simple terms, a limiting reagent is a reactant that is completely used up in the reaction. 

It is also referred to as a limiting reactant or limiting agent.

Now, according to the question,

Since it is a limiting reagent, it will react fully. 

The mass of AgCO_{3} that will be produced will be:-

Equivalent mole of AgNO_{3} = Equivalent weight of Ag_{2} CO_{3} = 12.7/169.97 = x*2/274x = 10.3 g. 

Hence, 10.3 g of Ag_{2} CO_{3} will be produced.

It is used to restrict the reaction.

It tells you the estimated amount of compound to be used.

It brings quantitative understanding to chemical reactions.

More information on limiting reagents can be found here :

brainly.com/question/11848702

#SPJ4

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What properties does a substance have to have to be a mineral?.
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the description of a mineral species usually includes its common physical properties such as habit, hardness, lustre, diaphaneity, colour, streak, tenacity, cleavage, fracture, parting, specific gravity, magnetism, fluorescence, radioactivity, as well as its taste or smell and its reaction to acid.

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The number of grams of H2 in 1470 mL of H2 gas. ​
Lorico [155]

Answer:

0.1313 g.

Explanation:

  • It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.
  • Suppose that hydrogen behaves ideally and at STP conditions.

<u><em>Using cross multiplication:</em></u>

1.0 mol of hydrogen occupies → 22.4 L.

??? mol of hydrogen occupies → 1.47 L.

∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.

  • Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:

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