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mojhsa [17]
1 year ago
5

. an ionic compound is composed of 34.95 g of iron and 15.05 g of oxygen. find the empirical formula of this compound.

Chemistry
1 answer:
Contact [7]1 year ago
3 0

Empirical formula of ionic compound is FeO. In which the composition of atoms is 1 : 1.

Empirical formula of an ionic compound is defined as the formula which gives whole number ratio of atoms of various elements present in molecule of compund.

mass of iron in compound = 34.95 g

molar mass of iron = 55.8 g

mass of oxygen in compound = 15.05 g

molar mass of oxygen = 32 g

number of moles of iron present in the compound are ratio of mass of iron in compound/ molar mass of iron

number of moles of iron in compound= 34.95 / 55.8 = 0.6263 ~ 1

number of moles oxygen in compound= 15.05/ 32 = 0.473 ~ 0.5

the ratio of the number of oxygen atoms to number of iron atoms present in one formula unit of iron compund is 2×0.5 / 1 = 1 : 1

Hence , the required empirical formula of iron compound is FeO.

To learn more about Emiprical formula, refer:

brainly.com/question/1439914

#SPJ4

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when the volume of a gas is changed from 3.75 L to 6.52 L the temperature will change from 100k to _K
harkovskaia [24]

The temperature will change from 100K to 173.87 K

calculation

by use of    law  that is V1/T1=V2/T2

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4 0
3 years ago
Read 2 more answers
How many Al atoms are there in 40.5 g of Al foil? Al:27
andrew-mc [135]

Answer:

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Explanation:

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Then use Avogadro's number which is 6.02 * 10^23

After that, write all of that down with dimensional analysis.

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As your final answer, you will get 9.03 * 10^23 atoms with sig figs.

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4 0
3 years ago
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5 0
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Marta_Voda [28]
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FinnZ [79.3K]
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3 years ago
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