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mojhsa [17]
1 year ago
5

. an ionic compound is composed of 34.95 g of iron and 15.05 g of oxygen. find the empirical formula of this compound.

Chemistry
1 answer:
Contact [7]1 year ago
3 0

Empirical formula of ionic compound is FeO. In which the composition of atoms is 1 : 1.

Empirical formula of an ionic compound is defined as the formula which gives whole number ratio of atoms of various elements present in molecule of compund.

mass of iron in compound = 34.95 g

molar mass of iron = 55.8 g

mass of oxygen in compound = 15.05 g

molar mass of oxygen = 32 g

number of moles of iron present in the compound are ratio of mass of iron in compound/ molar mass of iron

number of moles of iron in compound= 34.95 / 55.8 = 0.6263 ~ 1

number of moles oxygen in compound= 15.05/ 32 = 0.473 ~ 0.5

the ratio of the number of oxygen atoms to number of iron atoms present in one formula unit of iron compund is 2×0.5 / 1 = 1 : 1

Hence , the required empirical formula of iron compound is FeO.

To learn more about Emiprical formula, refer:

brainly.com/question/1439914

#SPJ4

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Answer:

Explanation:

The equation of the reaction is given as:

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Given parameters:

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Solution

From the balanced reaction equation, we can establish some mole ratios that would help solve the problem:

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therefore: 8 moles of NH₃ will be produced by  \frac{8 x 3}{2} = 12moles

So, 12 moles of hydrogen gas will react to give 8 moles of ammonia.

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 The equation shows that:

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6 0
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