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jolli1 [7]
1 year ago
15

What happens to the force between two objects if the mass of one object is doubled.

Physics
1 answer:
irinina [24]1 year ago
8 0

If the mass of one object is doubled, the force between these objects will also double.

Force refers to an external agent which is capable of changing the state of a body which may be at rest or in motion.

Force F = G(mM/d^2) (where m is the mass of first object, M is the mass of the second object and G is the gravitational pull and d is the distance between the two objects)

The force between two objects (m1 and m2) (according to the universal law of gravitation) is proportional to their mass and reciprocally proportional to the square of their separation between them.

So F' = G(2mM/d^2),

which means F'=2F

Therefore, the when the mass is doubled, the force also doubles.

To learn more about force, click

brainly.com/question/26115859

#SPJ4

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A water balloon launcher uses an elastic band with a spring constant of 115 N/m. To use the launcher, you stretch the band back
Lorico [155]

Here elastic balloon launcher will behave like an ideal spring

so here we have

spring constant k = 115 N/m

mass of balloon = 1.3 kg

Part a)

Stretch in the band is given as

x = 0.8 m

now the force on the balloon is given by

F = k x

now from above

F = (115) (0.8) = 92 N

so it will exert 92 N force on it

Part b)

Elastic potential energy is given as

U = \frac{1}{2}kx^2

so here we have

U = \frac{1}{2}(115)(0.8)^2

U = 36.8 J

Part c)

Here in this case we can say that kinetic energy gained by the balloon must be same as the elastic potential energy stored in the rubber because there is no energy loss in this system

So kinetic energy = 36.8 J

Part d)

As we know by the formula of kinetic energy

K = \frac{1}{2}mv^2

36.8 = \frac{1}{2}(1.3)v^2

v = 7.52 m/s

so speed of the balloon will be 7.52 m/s

7 0
3 years ago
Read 2 more answers
Acid mine drainage is:
Dahasolnce [82]

Answer:

Acid mine drainage is dissolved toxic materials wash from mines into nearby lakes and streams.

Explanation:

Acid mine drainage is the flow of acidic water with pH typically between 2 and 4, and high concentrations of other dissolved toxic materials from mines into nearby lakes and streams. It mainly occurs during metal sulfide mining, when the metal sulfide ore such as pyrite (FeS2) is exposed to water and oxygen from air to produce soluble iron and sulfuric acid.

Microorganisms, especially acidophile bacteria like Acidithiobacillus ferrooxidans grow by pyrite oxidation, i.e., oxidizing the Fe²⁺ in pyrite to Fe³⁺, which again react with pyrite and water to produce sulfuric acid. Then the acidic water flows into nearby water sources and reduces the pH value of water in those sources. As a result, heavy metals such as copper, lead, mercury, etc in other mineral ores also get dissolved into the water. The action of acidophile bacteria also increases the rate and degree of acid-mine drainage process.

The acid mine drainage causes water pollution and adversely affect the aquatic plants and animals. It also results in the contamination of drinking water, corrosion of infrastructures such as bridges, etc.

8 0
4 years ago
. What landform do you think this map depicts? a. Valley b. Mountain C. Plain​
nikklg [1K]
Isn’t that a mountain because it’s going up to the middle
6 0
3 years ago
7. What is the force of air resistance on an
Murrr4er [49]

Answer:

C) 464 N

Explanation:

The equation of the forces acting on the skydiver is:

mg-R=ma

where

(mg) is the weight of the skydiver, acting downward, with

m being the mass of the skydiver

g is the acceleration of gravity

R is the air resistance, acting upward

a is the acceleration of the skydiver

In this problem:

m = 80 kg

g = 9.8 m/s^2

a = 4.0 m/s^2

Solving the equation for R, we find the force of air resistance:

r=mg-ma=m(g-a)=(80)(9.8-4.0)=464 N

7 0
3 years ago
The suspension system of a 2100 kg automobile "sags" 8.5 cm when the chassis is placed on it. Also, the oscillation amplitude de
Gennadij [26K]

Answer:

Part a)

k = 6.06 \times 10^4 N/m

Part b)

b = 1795.4 kg/s

Explanation:

Part a)

as the mass of the suspension system is given as

m = 2100 kg

also we have

x = 8.5 cm

so now for force balance we have

mg = kx

(525)(9.81) = k(0.085)

k = 6.06 \times 10^4 N/m

Part b)

Now we know that amplitude decreases by 63% in each cycle

so after one cycle the amplitude will become 37% of initial amplitude

so it is given as

A = 0.37 A_o

also we know

A = A_o e^{-bt/2m}

0.37 A_o = A_o e^{-bt/2m}

\frac{bt}{2m} = 1

b = \frac{2m}{t}

here t = time period of one oscillation

so it is

t = 2\pi\sqrt{\frac{m}{k}}

t = 2\pi\sqrt{\frac{525}{6.06 \times 10^4}}

t = 0.58 s

now damping constant is

b = \frac{2(525)}{0.58}

b = 1795.4 kg/s

7 0
4 years ago
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