Given two different resistances, how does the rate of joule heating in them differ if they are connected to a fixed voltage sour
1 answer:
In series combination less rate of joule hating should be observed as compared to when connected in parallel combination .
Joule heating, also known as resistive, resistance, or Ohmic heating, is the process by which the passage of an electric current through a conductor produces heat.
Joule's first law states that the power of heating generated by an electrical conductor equals the product of its resistance and the square of the current:
When two or more resistors are connected end to end consecutively, they are said to be connected in series combination. The combined resistance of any number of resistances connected in series is equal to the sum of the individual resistances.
When two or more resistances are connected between the same two points, they are said to be connected in parallel combination. The reciprocal of the combined resistance of a number of resistances connected in parallel is equal to the sum of the reciprocals of all the individual resistances.
Rate of joule heating can be calculated by the formula
Power = / R
V = voltage
R = resistance
When both are connected in series than their equivalent resistance will be more as compared to when they are connected in parallel.
Power is inversely related to resistance , if voltage is constant
In series combination less rate of joule hating should be observed as compared to when connected in parallel
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I have attached the image showing the 6 combination of charges
Answer:
Smallest are: q1 = +1 nc, q2 = +1 nc, q3 = +1 nc and q1 = -1 nc, q2 = -1 nc, q3 = -1nc
Third Largest: q1 = +1 nc, q2 = +1nc, q3 = -1 nc
Second Largest: q1 = +1 nc, q2 = -1 nc, q3 = +1 nc
Largest are: q1 = +1 nc, q2 = -1 nc, q3 = -1 nc and q1 = -1 nc, q2 = +1 nc, q3 = +1 nc
Explanation:
The electrostatic force between 2 charges is; F = k•q1•q2/r²
Where r is the distance between the 2 charges q1 and q2 and k is coulombs constant.
Thus;
F ∝ q1•q2/r²
The net force on the charge q1 is the sum of the forces on charge q2 and q3.
If the two charges are opposite, the force is an attractive force while if the two charges are similar, the force is a repulsive force.
Thus, if the combination has same type of charges, i.e;(+1,+1,+1) or (-1,-1,-1), the force will be very small.
So, now the order of forces from smallest to largest is;
Smallest are: q1 = +1 nc, q2 = +1 nc, q3 = +1 nc and q1 = -1 nc, q2 = -1 nc, q3 = -1nc
Third Largest: q1 = +1 nc, q2 = +1nc, q3 = -1 nc
Second Largest: q1 = +1 nc, q2 = -1 nc, q3 = +1 nc
Largest are: q1 = +1 nc, q2 = -1 nc, q3 = -1 nc and q1 = -1 nc, q2 = +1 nc, q3 = +1 nc
Explanation:
Given that,
Charge acting on the object,
Force acting on the object, (in downward direction)
(a) The electric force acting in the electric field is given by :
E is the electric field
E = 4.75 N/C
The direction of electric field is as same as electric force. But it is negative charge. So, the direction of electric field is in upward direction.
(b) The charge on the proton is,
The force acting on the proton is :
If the charge on the proton is positive, the force on the proton is in upward direction.
Hence, this is the required solution.