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KiRa [710]
2 years ago
11

Given two different resistances, how does the rate of joule heating in them differ if they are connected to a fixed voltage sour

ce in series and in parallel?
Physics
1 answer:
Mkey [24]2 years ago
3 0

In series combination less rate of joule hating should be observed as compared to when connected in parallel combination .

Joule heating, also known as resistive, resistance, or Ohmic heating, is the process by which the passage of an electric current through a conductor produces heat.

Joule's first law states that the power of heating generated by an electrical conductor equals the product of its resistance and the square of the current:

When two or more resistors are connected end to end consecutively, they are said to be connected in series combination. The combined resistance of any number of resistances connected in series is equal to the sum of the individual resistances.

When two or more resistances are connected between the same two points, they are said to be connected in parallel combination. The reciprocal of the combined resistance of a number of resistances connected in parallel is equal to the sum of the reciprocals of all the individual resistances.

Rate of joule heating can be calculated by the formula

Power = V^{2} / R

V = voltage

R = resistance

When both are connected in series than their equivalent resistance will be more as compared to when they are connected in parallel.

Power is inversely related to resistance , if voltage is constant

In series combination less rate of joule hating should be observed as compared to when connected in parallel

To learn more about series combination here

brainly.com/question/16800236

#SPJ4

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Nookie1986 [14]

Answer:

<h2>0.245cm/min</h2>

Explanation:

The volume of the spherical balloon is expressed as V = 4/3πr³ where r is the radius of the spherical balloon. If the spherical balloon is inflated with gas at the rate of 500 cubic centimetres per minute then dV/dt = 500cm³.

Using chain rule to express dV/dt;

dV/dt = dV/dr*dr/dt

dr/dt is the rate at which the radius of the gallon is increasing.

From the formula, dV/dr = 3(4/3πr^3-1))

dV/dr = 4πr²

dV/dt = 4πr² *dr/dt

500 =  4πr² *dr/dt

If radius r = 40;

500 = 4π(40)² *dr/dt

500 = 6400π*dr/dt

dr/dt = 500/6400π

dr/dt = 5/64π

dr/dt  = 0.245cm/min

Hence, the radius of the balloon is increasing at the rate of 0.245cm/min

8 0
3 years ago
Am radio signals have frequencies between 550 khz and 1600 khz (kilohertz) and travel with a speed of 3.00 ✕ 108 m/s. what are t
Allisa [31]
The minimum frequency is 
f_1 = 550 kHz = 5.50 \cdot 10^5 Hz
while the maximum frequency is
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\lambda_1 =  \frac{v}{f_1}= \frac{3 \cdot 10^8 m/s}{5.5 \cdot 10^5 Hz}=545 m
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So, the wavelengths of the radio waves of the problem are within the range 188-545 m.

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Because why calculating displacement you only take two points in time, in this situation being the initial position and the final position. The distance between these two points is 12 kilometers.
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Vlad1618 [11]
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