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Nitella [24]
3 years ago
12

Am radio signals have frequencies between 550 khz and 1600 khz (kilohertz) and travel with a speed of 3.00 ✕ 108 m/s. what are t

he wavelengths of these signals?
Physics
1 answer:
Allisa [31]3 years ago
5 0
The minimum frequency is 
f_1 = 550 kHz = 5.50 \cdot 10^5 Hz
while the maximum frequency is
f_2 = 1600 kHz = 1.6 \cdot 10^6 Hz
Using the relationship between frequency f of a wave, wavelength \lambda and the speed of the wave v, we can find what wavelength these frequencies correspond to:
\lambda_1 =  \frac{v}{f_1}= \frac{3 \cdot 10^8 m/s}{5.5 \cdot 10^5 Hz}=545 m
\lambda_2 =  \frac{v}{f_2}= \frac{3 \cdot 10^8 m/s}{1.6 \cdot 10^6 Hz}=188 m

So, the wavelengths of the radio waves of the problem are within the range 188-545 m.

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How much of the matter in the universe is comprised of atoms?
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Explanation:

Atoms are the components of ordinary matter, also called baryonic matter, which only represents 4% of the universe, while the remaining 96% would be formed by what is known as dark matter and dark energy which constitute two of the unsolved problems in physics.

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The faster am igneous rock cools the_ the crystal size
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Bigger is the correct answer. the faster an igneous rock cools the bigger the bigger the crystal size will be
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Convert 400 mm to m using the method of dimensional analysis
s2008m [1.1K]

Answer:

To convert 400 mm to m you can apply the formula [m] = [mm] / 1000; use 400 for mm. Thus, the conversion 400 mm m is the result of dividing 400 by 1000. 0.4

<em>PLEASE</em><em> </em><em>MARK</em><em> </em><em>AS</em><em> </em><em>BRAINLIEST</em><em> </em><em>ANSWER</em><em> </em>

7 0
2 years ago
Three beads are placed along a thin rod. The first bead, of mass m1 = 23 g, is placed a distance d1 = 1.1 cm from the left end o
Mila [183]

Answer:

a) x=\frac{m_{1}d_{1}+m_{2}(d_{1}+d_{2})+m_{3}(d_{1}+d_{2}+d_{3}  ) }{m_{1}+m_{2}+m_{3} }

b) x = 4.47 cm

c) x=\frac{m_{1}d_{2}+m_{2}(0)+m_{3}d_{3} }{m_{1}+m_{2}+m_{3} }

d) x = 1.48 cm

Explanation:

a) The center of mass is equal to:

x=\frac{m_{1}x_{1}+m_{2}x_{2}+m_{3}x_{3} }{m_{1}+m_{2} +m_{3}}

Where m is the mass of beads and x is the distances, if x₁ = d₁, x₂ = d₂ and x₃ = d₃

x=\frac{m_{1}d_{1}+m_{2}(d_{1}+d_{2})+m_{3}(d_{1}+d_{2}+d_{3}  ) }{m_{1}+m_{2}+m_{3} }

b) If

m₁ = 23g

m₂ = 15 g

m₃ = 58 g

d₁ = 1.1 cm

d₂ = 1.9 cm

d₃ = 3.2 cm

x=\frac{23*1.1+15*(1.1+1.9)+58(1.1+1.9+3.2) }{23+15+58 } =4.47cm

c) The center of the mass of the beads realtive to the center of bead is:

x=\frac{m_{1}d_{2}+m_{2}(0)+m_{3}d_{3} }{m_{1}+m_{2}+m_{3} }

d) x=\frac{23*(-1.9)+(15*0)+(58*3.2) }{23+15+58 } =1.48cm

6 0
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The velocity of the wave involved in the Doppler effect:
Margarita [4]

The Doppler Effect provides the equation for the calculation of apparent frequency:

f=fo[vo/(vo-vr)] 

where:<span>
vo=source wave velocity 
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fo=source frequency </span>

<span>
The velocity of the doppler wave is 
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where λ is light wavelength. Hence,

v=λfo[vo/(vo-vr)] 

Based on the equation, we can say that wave velocity will always be defined by one and only one wavelength.

Therefore the answer is letter C.

<span> </span>

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