Answer: [Kr] 5s24d10 is the element Cadmium, Cd. It has 48 electrons.
Answer:
Redox reaction and single displacement
Explanation:
This reaction is first of all a redox reaction. A redox reaction is a reaction that involves both oxidation and reduction. Oxidation involves increase in oxidation number while reduction involves decrease in oxidation number.
Copper (Cu) had an oxidation number of "0" as a reactant but had an oxidation number of "2+" in the product [Cu(NO₃)₂] hence oxidation occurred.
Nitrogen (N) had an oxidation number of "5+" in the reactant (HNO₃) but had an oxidation number of "4+" in the product (NO₂) hence reduction also occurred.
Also, from the reaction, it can be deduced that copper (Cu) displaced hydrogen (H) from the nitric acid (HNO₃) solution to form copper (II) nitrate [Cu(NO₃)₂]. It should be noted that copper can displace hydrogen because it is higher than hydrogen in the electrochemical series. Hence, this reaction can also be called a single displacement reaction. A single displacement reaction is a reaction in which an atom of an element replaces another atom in a compound (as seen in the equation given in the question).
Answer:
1) 7.256 mol Br2 (Cl2)/(Br2)
The Br2 cancels out, so we have 7.256(2)
This is 14.512.
2) Number of moles = mass / molar mass
Number of moles = 239.7 g/ 35.5 g/mol
Number of moles = 6.8 mol
BrCl=13.6 mol
13.6(11.5.357)
1568.9 g
3) Repeat the same process with problem 2, given that there are 6.022x10^23 atoms in a mole.
Explanation:
Br2 + Cl2 → 2BrCl
Answer:
Explanation:
2 NH4I + Pb(NO3)2 = PbI2 + 2 NH4NO3
2 mol 1 mol
x ml 751 ml
0.550 M 0.380 M
0.380 mol/1000 ml x 751 ml = 0.285 mol Pb(NO3)2
0.285 mol Pb(NO3)2 x 2 mol NH4I/1 mol Pb(NO3)2=0.571 mol NH4I needed
0.571 mol NH4I/0.550 mol/1000 ml=1038 ml
<span>B, An Arrhenius acid donates H+ ions.</span>
