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Art [367]
3 years ago
6

There is always some between any surfaces that are in contact with each other.

Chemistry
1 answer:
exis [7]3 years ago
4 0

Answer:

pls brain list me :(

Explanation:

Friction. Friction

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when methane reacts with oxygen, the products are carbon dioxide and water. How many grams of carbon dilxide are formed if 30 g
Wittaler [7]

Answer:

CH4+2O2→CO2+2H2O

Moles of oxygen=3232=1

Moles of carbon dioxide=4422=0.5

Moles of water=1818=1

1 mole of methane reacts with 2 moles of oxygen to give 1 mole of CO2 and 2 moles of water so 0.5 mole of methane will be required which is equal to 0.5×16=8g.

Explanation:

8g

4 0
2 years ago
Of the following gases, ________ will have the greatest rate of effusion at a given temperature. Of the following gases, _______
kolezko [41]

<u>Answer:</u> From the given gases, the greatest rate of effusion is of CH_4

<u>Explanation:</u>

Rate of effusion of a gas is determined by a law known as Graham's Law.

This law states that the rate of effusion or diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

It is visible that molar mass is inversely related to rate of effusion. So, the gas having lowest molar mass will have the highest rate of effusion.

For the given gases:

Molar mass of NH_3=17g/mol

Molar mass of HCl=36.5g/mol

Molar mass of CH_4=16g/mol

Molar mass of Ar=40g/mol

Molar mass of HBr=81g/mol

The molar mass of methane gas is the lowest. Thus, it will have the greatest rate of effusion.

Hence, the greatest rate of effusion is of CH_4

8 0
4 years ago
How much oxygen be required to produce 3.9 mol of water
timofeeve [1]

Answer:

1.95mol

Explanation:

First let us generate the equation for the reaction:

2H2 + O2 —> 2H2O

From the equation,

1mole of O2 reacted to produce 2moles of H2O.

Therefore, Xmol of O2 will react to produce 3.9 mol of H2O i.e

Xmol of O2 = 3.9/2 = 1.95mol

6 0
3 years ago
Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.
Minchanka [31]

Answer:

Mn(NO3)3 Molar mass = (54.93) + (3 x 14) + (9 x 16) = 240.93g/mol

Total number of Oxygen atoms in formula = 9

Total mass of oxygen atoms theoretically in the formula = 9x16 = 144g/mol

Oxygen's percentage composition:

(144/240.93) x 100 = 59.7% of the compound is oxygen

6 0
3 years ago
Which source of evidence did Wegener use to support his theory of continental drift?
zzz [600]

Answer: The Answer is A. Fossils

Explanation: I got the question correct on my quiz, therefore it is Fossils.

5 0
3 years ago
Read 2 more answers
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