Answer:
CH4+2O2→CO2+2H2O
Moles of oxygen=3232=1
Moles of carbon dioxide=4422=0.5
Moles of water=1818=1
1 mole of methane reacts with 2 moles of oxygen to give 1 mole of CO2 and 2 moles of water so 0.5 mole of methane will be required which is equal to 0.5×16=8g.
Explanation:
8g
<u>Answer:</u> From the given gases, the greatest rate of effusion is of 
<u>Explanation:</u>
Rate of effusion of a gas is determined by a law known as Graham's Law.
This law states that the rate of effusion or diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

It is visible that molar mass is inversely related to rate of effusion. So, the gas having lowest molar mass will have the highest rate of effusion.
For the given gases:
Molar mass of 
Molar mass of 
Molar mass of 
Molar mass of 
Molar mass of 
The molar mass of methane gas is the lowest. Thus, it will have the greatest rate of effusion.
Hence, the greatest rate of effusion is of 
Answer:
1.95mol
Explanation:
First let us generate the equation for the reaction:
2H2 + O2 —> 2H2O
From the equation,
1mole of O2 reacted to produce 2moles of H2O.
Therefore, Xmol of O2 will react to produce 3.9 mol of H2O i.e
Xmol of O2 = 3.9/2 = 1.95mol
Answer:
Mn(NO3)3 Molar mass = (54.93) + (3 x 14) + (9 x 16) = 240.93g/mol
Total number of Oxygen atoms in formula = 9
Total mass of oxygen atoms theoretically in the formula = 9x16 = 144g/mol
Oxygen's percentage composition:
(144/240.93) x 100 = 59.7% of the compound is oxygen
Answer: The Answer is A. Fossils
Explanation: I got the question correct on my quiz, therefore it is Fossils.