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Mandarinka [93]
2 years ago
11

This is a science multiple choice question. I am posting this for the third time because the people who answered it posted a lin

k and when I copied and pasted it to see the answer, it didn't work so please answer correctly without A LINK! Please whoever answers this without posting a link to the answer will be marked brainliest.
I appreciate it, thanks.

Chemistry
2 answers:
Aleks04 [339]2 years ago
6 0

Answer: I'd say Seafloor spreading.

Aleks04 [339]2 years ago
6 0
I believe the answers would be continental drift, sea floor spreading, and lithosphere.

All of these have something to do with plate tectonics.
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A substance which contains various elements or compounds without bonding or in fixed proportions is a(n) _____.
julia-pushkina [17]
The correct answer that would best complete the given statement above would be the word MIXTURE. <span>A substance which contains various elements or compounds without bonding or in fixed proportions is a mixture. When a chemical union occurs, this is when a compound is being formed. Hope this answer helps.</span>
5 0
3 years ago
Which member of each pair is the stronger base? part a ethylamine or aniline ethylamine or aniline ethylamine aniline request an
Vladimir79 [104]
Lowery-Bronsted theory is applied here. Acc. to this theory Base accepts protons and Acids donate proton.

Part 1: 
Aniline is less basic than ethylamine because the lone pair on nitrogen (which accepts proton) is not localized. It resonates throughout the conjugated system of phenyl ring. Hence due to unavailability of electrons for accepting proton it is less basic compare to ethylamine. In ethyl amine the lone pair of electron is localized and available to abstract proton.

Part 2:
In this case the alkyl groups attached to -NH₂ (in ethylamine) and -O⁻ (in ethoxide are same (i.e. CH₃-CH₂-). Ethoxide is more basic than ethylamine because ethoxide is a conjugate base of ethanol (pKa value of ethanol = 15.9 very weak acid) and the conjugate base of weak acid is always a strong base. Secondly, the oxygen atom more Electronegative than Nitrogen atom can attract more electron cloud from alkyl group as compared to Nitrogen in ethylamine. Hence, oxygen in ethoxide attains greater electron cloud than the nitrogen in ethylamine. Therefore, it is more basic than ethylamine.

5 0
3 years ago
Murcury is the only metal at room temperature. Its density is 13.6g/mL. How many grams of murcury will occupy a volume of 95.8mL
Hatshy [7]

Answer:

<h3>The answer is 1.30288 × 10³ g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 95.8mL

density = 13.6g/mL

We have

mass = 13.6 × 95.8 = 1302.88

We have the final answer as

<h3>1.30288 × 10³ g</h3>

Hope this helps you

3 0
3 years ago
For a first-order reaction, A → B, the rate coefficient was found to be 3.4 × 10-4 s-1 at 23 °C. After 5.0 h, the concentration
Illusion [34]

Answer:

the original concentration of A = 0.0817092  M

Explanation:

A reaction is considered to be of first order it it strictly obeys the graphical equation method.

k_1 = \dfrac{2.303}{t}log \dfrac{a}{a-x}

where;

k = the specific rate coefficient  = 3.4 × 10⁻⁴ s⁻¹

t = time   = 5.0 h = 5.0 × 3600 = 18000 seconds

a = initial concentration = ???

a - x = remaining concentration of initial concentration at time t = 0.00018 mol L⁻¹

3.4 \times 10^{-4}= \dfrac{2.303}{18000}log \dfrac{a}{0.00018}

3.4 \times 10^{-4}= 1.27944 \times 10^{-4} \times log \dfrac{a}{0.00018}

\dfrac{3.4 \times 10^{-4}}{1.27944 \times 10^{-4}}=   log \dfrac{a}{0.00018}

2.657=   log \dfrac{a}{0.00018}

10^{2.657}= \dfrac{a}{0.00018}

453.94 = \dfrac{a}{0.00018}

a =453.94 \times 0.00018

a = 0.0817092  M

Thus , the original concentration of A = 0.0817092  M

8 0
3 years ago
The lower the percent of energy required for a machine to perform work, the more energy efficient it is. Please select the best
Anvisha [2.4K]
Hey You!

The Correct Answer Is: True.

I Really Hope This Helped You, Good Luck With Your Studies! =)
3 0
2 years ago
Read 2 more answers
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