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mezya [45]
2 years ago
9

You have a fourth rock. You drop it off the building with an initial speed of zero, but from the same height that you threw the

first three rocks.
The fourth rock hits the ground with a speed of 12 m/s Also, the rock you threw horizontally hit the ground with a speed of 13 m/s

What is v othe initial speed at which you threw the first three rocks?
Physics
1 answer:
kogti [31]2 years ago
8 0

The initial speed at which you threw the first three rocks is 13 m/s.

<h3>What is horizontal component of velocity?</h3>

The horizontal velocity component (vx) describes the influence of the velocity in displacing the projectile horizontally.

The horizontal component of velocity remains constant as their is no force in the horizontal direction.

The initial speed at which you threw the first three rocks is calculated as follows;

v(xi) = v(xf)

where;

  • v(xi) is initial horizontal speed
  • v(xf) is the final horizontal speed

v(xf) = 13 m/s = v(xi)

Thus, the initial speed at which you threw the first three rocks is 13 m/s.

Learn more about horizontal speed here: brainly.com/question/24949996

#SPJ1

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