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olya-2409 [2.1K]
2 years ago
12

A student creates a scale model of planets where 1 centimeter (cm) is equal to 10,000 kilometers (km). In this model, which plan

et would have a diameter of approximately 12 cm?
Chemistry
1 answer:
Arlecino [84]2 years ago
3 0

The planet that would have a diameter of approximately 12 cm is Saturn.

<h3>What is a scale model?</h3>

A scale model is a model which is used to represent another object using a given scale.

Scale models can be used to make small object bigger or larger objects smaller.

Considering the scale model of the planets where  1 centimeter (cm) is equal to 10,000 kilometers (km);

1 centimeter = 10,000 kilometers

12 centimeter = 1.2 × 10⁵ kilometers

The planet with a diameter of approximately 1.2 × 10⁵ kilometers is Saturn.

In conclusion, scale models are used to model objects.

Learn more about scale models at: brainly.com/question/17595659
#SPJ1

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[H^{+}] = 0.761 \frac{mol}{L}

[OH^{-}]=1.33X10^{-14}\frac{mol}{L}

pH = 0.119

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HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L)  \\ n_{H^{+} } from HNO_{3}  = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)

Here, n is the number of moles and V is the volume. From the given data moles can be calculated as follows

n_{H^{+} } from HCl = (5.00)(0.093)

n_{H^{+} } from HCl = 0.465 mol

n_{H^{+} } from HNO_{3}  = (8.00)(0.037)

n_{H^{+} } from HNO_{3}  = 0.296 mol

n_{H^{+}(total) } = 0.296 + 0.465

n_{H^{+}(total) } = 0.761 mol

For molar concentration of hydrogen ions:

[H^{+}]  = \frac{n_{H^{+}}(mol)}{V(L)}

[H^{+}] = \frac{0.761}{1.00}

[H^{+}] = 0.761 \frac{mol}{L}

From dissociation of water (Kw = 1.01 X 10⁻¹⁴ at 25°C) [OH⁻] can be determined as follows

K_{w} = [H^{+} ][OH^{-} ]

[OH^{-}]=\frac{Kw}{[H^{+}] }

[OH^{-}]=\frac{1.01X10-^{-14}}{0.761 }

[OH^{-}]=1.33X10^{-14}\frac{mol}{L}

The pH of the solution can be measured by the following formula:

pH = -log[H^{+} ]

pH = -log(0.761)

pH = 0.119

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