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olya-2409 [2.1K]
2 years ago
12

A student creates a scale model of planets where 1 centimeter (cm) is equal to 10,000 kilometers (km). In this model, which plan

et would have a diameter of approximately 12 cm?
Chemistry
1 answer:
Arlecino [84]2 years ago
3 0

The planet that would have a diameter of approximately 12 cm is Saturn.

<h3>What is a scale model?</h3>

A scale model is a model which is used to represent another object using a given scale.

Scale models can be used to make small object bigger or larger objects smaller.

Considering the scale model of the planets where  1 centimeter (cm) is equal to 10,000 kilometers (km);

1 centimeter = 10,000 kilometers

12 centimeter = 1.2 × 10⁵ kilometers

The planet with a diameter of approximately 1.2 × 10⁵ kilometers is Saturn.

In conclusion, scale models are used to model objects.

Learn more about scale models at: brainly.com/question/17595659
#SPJ1

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How much force is needed to accelerate a 56 kg skier at 3 m/s?
Aloiza [94]

Answer:

<h2>168 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 56 × 3

We have the final answer as

<h3>168 N</h3>

Hope this helps you

3 0
3 years ago
A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a
svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = 62.364\text{ L. Torr }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

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Explanation:

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