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alexgriva [62]
1 year ago
7

Horticulturists know that, for many plants, dark green leaves are associated with low light levels and pale green with high leve

ls. (a) Use the photon theory to explain this behavior.
Chemistry
1 answer:
nikitadnepr [17]1 year ago
7 0
  • In the reduction process of photosynthesis, electrons are transported from water to carbon dioxide.
  • According to photon theory here the photons behave as light energy particle.
  • By capturing sun energy (photons), chlorophyll aids in this process.An electron in the chlorophyll molecule gets excited from a lower to a higher energy state when chlorophyll receives energy from sunlight.
  • Excessive sunshine is the main cause of leaves turning a darker green color. Lack of sunlight causes a plant's leaves to create more chlorophyll, which is what gives the plant its green hue.
  • The color of the leaf is darker green than typical because of the increase in chlorophyll concentration per unit area.
<h3>What is photon theory?</h3>

The photon theory of light states that photons have simultaneous particle and wave behavior. pass through empty space at a constant speed, or "the speed of light". possess rest energy and zero mass.

Learn more about photon theory here:

brainly.com/question/3479307

#SPJ4

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First, we have to remember the molarity formula:

M=\text{ }\frac{moles\text{ of solute}}{L\text{ solution}}

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In this case, our solute is sodium nitrate (NaNO3), and we have the mass dissolved in water, then we have to convert grams to moles. For that, we need the molecular weight:

M.W_{NaNO_3}=\text{ 23+14+16*3= 85 g/mol}

Then, we calculate the moles present in the solution:

3.976\text{ g NaNO}_3\text{ * }\frac{1\text{ mol}}{85\text{ g}}=\text{ 0.04678 mol NaNO}_3

Now, we have the necessary data to calculate the molarity (with the solution volume of 200 mL):

M=\frac{0.04678\text{ mol}}{200\text{ mL*}\frac{1\text{ L}}{1000\text{ mL}}}=\text{ 0.2339 M}

The molarity of this solution equals 0.2339 M.

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In this case, we have the same amount (in moles and mass) of sodium nitrate, but a different volume of solution, then we only have to change it:

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