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miskamm [114]
4 years ago
10

PLEASE HELP WILL REWARD BRAINLIEST

Chemistry
1 answer:
klasskru [66]4 years ago
6 0
The first option is the correct one.
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For the complete combustion of 47 g of gasoline (octane, C8H18) , the mass of oxygen consumed is
aleksklad [387]

Answer: d) 164.9 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}     \text{Moles of octane}=\frac{47g}{114g/mol}=0.412moles

The balanced chemical reaction is:

2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)  

According to stoichiometry :

2 moles of C_8H_{18} require = 25  moles of O_2

Thus 0.412 moles of C_8H_{18} will require=\frac{25}{2}\times 0.412=5.15moles  of O_2

Mass of O_2=moles\times {\text {Molar mass}}=5.15moles\times 32g/mol=164.9g

Thus 164.9 g of oxygen is consumed.

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