The empirical formula is SCl_2.
The <em>empirical formula</em> (EF) is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the <em>molar ratio </em>of S to Cl.
Assume that you have 100 g of sample.
Then it contains 31.14 g S and 68.86 g Cl.
<em>Step</em> 1. Calculate the <em>moles of each element</em>
Moles of S = 31.14 g S × (1 mol S/(32.06 g S) = 0.971 30 mol S
Moles of Cl = 68.86 g Cl × (1 mol Cl/35.45 g Cl) = 1.9425 mol Cl
<em>Step 2</em>. Calculate the <em>molar ratio</em> of each element
Divide each number by the smallest number of moles and round off to an integer
S:Cl = 0.971 30: 1.9425 = 1:1.9998 ≈ 1:2
<em>Step 3</em>: Write the <em>empirical formula</em>
EF = SCl_2
Answer:
-0.050 kJ/mol.K
Explanation:
- A certain reaction is thermodynamically favored at temperatures below 400. K, that is, ΔG° < 0 below 400. K
- The reaction is not favored at temperatures above 400. K, that is. ΔG° > 0 above 400. K
All in all, ΔG° = 0 at 400. K.
We can find ΔS° using the following expression.
ΔG° = ΔH° - T.ΔS°
0 = -20 kJ/mol - 400. K .ΔS°
ΔS° = -0.050 kJ/mol.K
Answer:
Solution: Since the atomic mass of silver (Ag) is 107.87 amu, one mole of silver has a mass o f 107.87 grams. Therefore, there is one mole of Ag per 107.87 grams of Ag
Explanation:
Answer:
erosion, weathering, dissolution, precipitation, and lithification So,D.weathering and erosion followed by compaction
Explanation:
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