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3 years ago

What is a compound in chemistry

1 answer:

5 0

Two types of chemical bonds common in compounds are covalent bonds and ionic bonds. The elements in any compound are always present in fixed ratios. Example 1: Pure water is a compound made from two elements - hydrogen<span> and </span>oxygen<span>.</span>

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In the solution containing both 0.10 M acetic acid and 0.10 M sodium acetate, the acetic acid undergoes ionization. The chemical

Sedbober [7]

Answer:

percent ionization = 50.01%; pH = 4.75

Explanation:

To solve this question we must write the acetic acid equilibrium (Where HX will be acetic acid and X⁻ the sodium acetate):

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

Where equilibrium constant, Ka, is defined as:

Ka = 1.76x10⁻⁵ = [H⁺] [X⁻] / [HX]

<em>Where the concentration of each ion is:</em>

[H⁺] = X

[X⁻] = 0.10M + X

[HX] = 0.10M - X

Replacing in Ka expression:

1.76x10⁻⁵ = [X] [0.10-X] / [0.10+X]

1.76x10⁻⁶ + 1.76x10⁻⁵X = 0.10X - X²

X² - 0.0999824 X + 1.76×10⁻⁶ = 0

X ≈ 0.1M → False solution. Decreases a lot the concentration of HX

X = 0.0000176M → Right solution.

The concentration of each ion is:

[H⁺] = 0.0000176062M

[X⁻] = 0.10M + 0.0000176M = 0.1000176M

[HX] = 0.10M - 0.0000176M = 0.0999824M

Percent ionization:

[X-] / [X-] + [HX] * 100 =

0.1000176M / 0.2M =

And pH = -log [H+]

As you can see, [H+]≈ Ka

3 0

3 years ago

Convert 0.36 atm to kPa

Marrrta [24]

Answer:

36.36

Explanation:

Multiply pressure value by 101 for every problem like this.

8 0

3 years ago

Read 2 more answers

Select all the correct answers.

ikadub [295]

Answer:

it is The fuel used for fusion is abundant in nature and easy to obtain and The fusion process doesn’t require an energy input ans Fusion has fewer safety risks than fission. and Fusion doesn’t produce radioactive waste products.

Explanation:

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3 years ago

Read 2 more answers

Apakah kelebihan mempunyai suhu badan yang tetap

Mars2501 [29]

Answer:

bbabaaallalalalalalalalalalalsnkdbsisndizbsizbsiejeuebsiebduebsibeiwbafavaniabsisnao। an a sjs sjs sjs sjs sjs did sidnjsjs s suashshhsjaba s susbsje surbsuenjab

hsjsjajajsnsbeheh

Explanation:

hsoJnahabsb she did sjs usbsjshsoab sxb djdndjs s sjs is disq dx। xdho exoh exoh do so exoh exoh exoh sxp। woxnoppjwxbpjexbpojexbpex। exoh xoejx ojexbooojsxbjoohsx ojsx ojsx। zsp sxpje। xpjsxpoj exoh exoh spjx। ohsxxoohsx oh ihxw ipjsx oohsx oh exoh exoh sxo exoh exoh exoh wx exvodwhbwvdwwd

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3 years ago

The constant- pressure heat capacity of a sample of a perfect gas was found to vary with temperature according to the expression

vivado [14]

A perfect gas, commonly known as an ideal gas, would be a gas that, in physical behavior, conforms towards the general gas law, which would be a <u><em>specific, idealized relationship between pressure, volume, and temperature,</em></u> and further calculation can be defined as follows:

For question a:

$q=\int C_p dT=\int^{200+273K}_{25+273 K} [20.17 + 0.3665 (\frac{T}{K})] dT JK^{-1}\\\\$

$=[(20.17)T +\frac{1}{2}(0.3665)\times (\frac{T^2}{K})]^{473K}_{298K}\ JK^{-1}\\\\=[(20.17)\times(473-293) +\frac{1}{2}(0.3665)\times (473^2-293^2)]\ J\\\\=[(20.17)\times(180) +\frac{1}{2}(0.3665)\times (223729-85849)]\ J\\\\=[3630.6 +(0.18325)\times (137880)]\ J\\\\=[3630.6 +25266.51]\ J\\\\=[28897.11]\ J\\\\=[28.8 \times 10^{3}] \ J\\\\$

$W= -p \Delta V= -nR\Delta T= -(1.00\ mol) \times 8.3145\ J K^{-1}\ mol^{-1} \times 100\ K=-831\ J\\\\\Delta U= q+w=(28.8 -0.831)\ KJ= 27.969\ KJ\\\\$

For question b:

In this question, the energy and enthalpy of a perfect gas depend on temperature alone, therefore $\Delta H= 28.8 \ KJ$ and $\Delta U= 27.969\ KJ$ as above at constant volume $w=0$ and $\Delta U=q$ so, $q=27.969 \ KJ$ .

Learn more:

brainly.com/question/4270867

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3 years ago