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Morgarella [4.7K]
3 years ago
15

PLEASE HELP ASAP WITH THESE THREE!

Chemistry
1 answer:
Furkat [3]3 years ago
5 0

Answer:

001: 71.2 g per ML

002: Consider a block of marble that occupies 287 cm3 and has a mass of 869 g.

a. What is its density?

d=m/v=869g/287 cm3=3.03 g/cm3

b. Will it float in:

H2O(l)? Why or why not?

Nope! Density > 1.00 g/mL

Hg(l) (density=13.55 g/mL)? Why or why not?

Yep! Density < 13.55 g/mL

003:  

Use the given functions to set up and simplify  

0.309 cm3

g/cm3=g/cm3

0.309cm3=g/cm3

 

Explanation:

http://childschemistry.weebly.com/uploads/7/8/6/3/78638416/density_key.pdf

Hope this helps I tried my best

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If I made any mistakes in this please tell me now
sineoko [7]

Answer:

no u did not u did good

Explanation:

7 0
2 years ago
Balance the chemical equation. ___Mg + ___Fe2O^3 -&gt; ___MgO + ___Fe
VMariaS [17]

Answer:

3Mg + Fe₂O₃ → 3MgO + 2Fe.

Explanation:

  • To balance the equation, you should apply the law of conservation of mass for the equations.
  • The law of conservation of mass states that the no. of each atom is equal in both sides (reactants and products).
  • The balanced equation is:

<em>3Mg + Fe₂O₃ → 3MgO + 2Fe.</em>

<em></em>

That 3.0 mole of Mg react with 1.0 mole of Fe₂O₃ to produce 3.0 moles of MgO and 2.0 moles of Fe.

  • The no. of all atoms is the same in both of reactants and products side.

Mg (3), Fe (2), and O (3).

8 0
3 years ago
What is the formula for salt used for the green light in the fireplace
Y_Kistochka [10]
Hello R2o4!

The formula of salt used for green light is BaCl2
Cheers!
-Blizzard
5 0
3 years ago
How many atoms does one formula unit of Sb4(SiO4)3 have
kotegsom [21]

Answer:

There are 19 atom sin total in antimony silicate, Sb_4(SiO_4)_3.

Explanation:

Number of antimony atoms = 4 × 1 = 4

Number of silicon atoms = 3 × 1 = 3

Number of oxygen atoms = 3 × 4 = 12

Number of atoms in antimony silicate:

= 4 + 3 + 12 = 19

There are 19 atom sin total in antimony silicate, Sb_4(SiO_4)_3.

6 0
3 years ago
How many moles of copper are in 1.51 x 1024 Cu atoms?
kkurt [141]
<h3>Answer:</h3>

2.51 mol Cu

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.51 × 10²⁴ atoms Cu

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 1.51 \cdot 10^{24} \ atoms \ Cu(\frac{1 \ mol \ Cu}{6.022 \cdot 10^{23} \ atoms \ Cu})
  2. Multiply/Divide:                  \displaystyle 2.50747 \ mol \ Cu

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2.50747 mol Cu ≈ 2.51 mol Cu

8 0
3 years ago
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