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2 years ago

PLEASE HELP ASAP WITH THESE THREE!

Chemistry

1 answer:

Furkat [3]2 years ago

5 0

Answer:

001: 71.2 g per ML

002: Consider a block of marble that occupies 287 cm3 and has a mass of 869 g.

a. What is its density?

d=m/v=869g/287 cm3=3.03 g/cm3

b. Will it float in:

H2O(l)? Why or why not?

Nope! Density > 1.00 g/mL

Hg(l) (density=13.55 g/mL)? Why or why not?

Yep! Density < 13.55 g/mL

003:

Use the given functions to set up and simplify

0.309 cm3

g/cm3=g/cm3

0.309cm3=g/cm3

Explanation:

http://childschemistry.weebly.com/uploads/7/8/6/3/78638416/density_key.pdf

Hope this helps I tried my best

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Which trait is most likely a result of artificial selection

ycow [4]

Answer:

Explanation:Artificial selection is distinct from natural selection in that it describes selection applied by humans in order to produce genetic change. When artificial selection is imposed, the trait or traits being selected are known, whereas with natural selection they have to be inferred. In most circumstances and unless otherwise qualified, directional selection is applied, i.e., only high-scoring individuals are favored for a quantitative trait. Artificial selection is the basic method of genetic improvement programs for crop plants or livestock (see Selective Breeding). It is also used as a tool in the laboratory to investigate the genetic properties of a trait in a species or population, for example, the magnitude of genetic variance or heritability, the possible duration of and limits to selection, and the correlations among traits, including with fitness.

4 0

3 years ago

How many 3-liter balloons could the 12-L helium tank pressurized to 160 atm fill? Keep in mind that an "exhausted" helium tank i

vaieri [72.5K]

Answer:

The 12L helium tank pressurized to 160 atm will fill <em>636 </em>3-liter balloons

Explanation:

It is possible to answer this question using Boyle's law:

$P_1V_1=P_2V_2$

Where P₁ is the pressure of the tank (160atm), V₁ is the volume of the tank (12L), P₂ is the pressure of the balloons (1atm, atmospheric pressure) And V₂ is the volume this gas will occupy at 1 atm, thus:

160atm×12L = 1atm×V₂

V₂ = 1920L

As the tank will never be empty, the volume of the gas able to fill balloons is the total volume minus 12L, thus the volume of helium able to fill balloons is:

1920L - 12L = 1908L

1908L will fill:

1908L× $\frac{1balloon}{3L}$ = <em>636 balloons</em>

I hope it helps!

7 0

3 years ago

35. Which of the following atoms has the most possible bond sites?

Vadim26 [7]

Answer:

C phosphorus has 5 bond sites.

4 0

3 years ago

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How

BARSIC [14]

<h3>Answer:</h3>

6.21 × 10²² Carbon Atoms

<h3>Solution:</h3>

Data Given:

Mass of Butane (C₄H₁₀) = 1.50 g

M.Mass of Butane = 58.1 g.mol⁻¹

Step 1: Calculate Moles of Butane as,

Moles = Mass ÷ M.Mass

Putting values,

Moles = 1.50 g ÷ 58.1 g.mol⁻¹

Moles = 0.0258 mol

Step 2: Calculate number of Butane Molecules;

As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Butane Molecules can be written as,

Moles = Number of C₄H₁₀ Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Butane molecules,

Number of C₄H₁₀ Molecules = Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting value of moles,

Number of C₄H₁₀ Molecules = 0.0258 mol × 6.022 × 10²³ Molecules.mol⁻¹

Number of C₄H₁₀ Molecules = 1.55 × 10²² C₄H₁₀ Molecules

Step 3: Calculate Number of Carbon Atoms:

As,

1 Molecule of C₄H₁₀ contains = 4 Atoms of Carbon

So,

1.55 × 10²² C₄H₁₀ Molecules will contain = X Atoms of Carbon

Solving for X,

X = (1.55 × 10²² C₄H₁₀ Molecules × 4 Atoms of Carbon) ÷ 1 Molecule of C₄H₁₀

X = 6.21 × 10²² Atoms of Carbon

5 0

3 years ago

Read 2 more answers

Calculate the number of atoms of copper represented by 127.08 g of copper.

frosja888 [35]

The molar mass of copper is 63.55 g/mol. So, you convert grams to moles 127.08/63.55 =1.999 moles copper. Now, 1 mole = 6.022e23 atoms, so multiply # of moles by 6.022e23. 1.999 x 6.022e23= # of atoms of copper.

7 0

3 years ago