It is used when a slope is too steep or when there is no alternative method of preventing soil erosion. The most common crop<span> choices for </span>strip cropping<span> are closely sown crops such as hay, wheat, or other forages which are alternated with</span>strips<span> of row crops, such as corn, soybeans, cotton, or sugar beets.</span>
Answer:
volume = 972.23ml
Explanation:
using general gas law
P1V1/T1 = P2V2/T2
765 x 585/293 = 443 x V2/282
1527.39 =443 x V2/282
1527.38 x 282 = 443 x V2
430695.78 = 443 x V2
V2 = 430695.68/443
V2 = 972.23mL
This impurity is troubling from an economic standpoint because it lead to decrease in the yield of phosphorus
- Ferrophosphorus is a byproduct of phosphorus production in submerged-arc furnaces , by their reduction with carbon. It is formed from the iron oxide impurities.
- Iron impurities present in the calcium phosphate will be precipitated out as the iron phosphate which eventually will lead to the decrease in the yield of phosphorous during the production of phosphorous.
Thus we can conclude that Fe₂P causes decrease in yield
Learn more about production of phosphorus at brainly.com/question/13337198
#SPJ4
Answer:
1. Balanced chemical for the given chemical reaction is :

number of mole of sulphuric acid produced = 12.5 mol
number of mole of oxygen required=6.25 mol
Explanation:
1. Balanced chemical for the given chemical reaction is :

from above balanced equation it is clearly that ,
2 mole of sulpher dioxide gives 2 mole of sulphuric acid
1 mole of sulpher dioxide gives 1 mole of sulphuric acid
therefore,
12 .5 mole of sulpher dioxide will givs 12.5 mole of sulphuric acid
number of mole of sulphuric acid produced = 12.5 mol
2 mole of sulphur dioxide needs 1 mole of oxygen gas
so,
1 mole of sulphur dioxide needs 0.5 mole of oxygen gas
therefore 12.5 of sulphur dioxide needs
mole of oxygen
number of mole of oxygen required=6.25 mol
This is a combined gas law problem, according to which

where P is the pressure of the gas, V is the volume of the gas, and T is the temperature of the gas, and the subscripts 1 and 2 correspond to the initial and final conditions of the gas. In this problem, we are given the initial pressure, volume, and temperature of the gas in the balloon:
P₁ = 1.0 atm
V₁ = 1.8 L
T₁ = 295.15 K (K = °C + 273.15).
Moreover, we are given the final pressure and temperature of the gas in the balloon.
P₂ = 0.86 atm
T₂ = 281.15 K.
What we want to find is the final volume, V₂, which we can obtain by rearranging the combined gas equation to solve for V₂:

This answer has three significant figures. However, the question as written would warrant an answer that comprises one significant figure (as 8 °C has only one sig fig). In that case, the answer would be 2 L. If the answer is to be given to two significant figures, the volume would then be 2.0 L.