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melomori [17]
2 years ago
14

State and explain the relative change in the pH and in the buffer-component concentration ratio, [NaA]/[HA], for each of the fol

lowing additions:(d) Dissolve pure HA in the buffer
Chemistry
1 answer:
melisa1 [442]2 years ago
8 0

When pure HA is added to the buffer, the buffer component ratio and the pH decrease.

<h3>State and explain the relative change in the pH and in the buffer-component concentration ratio, [NaA]/[HA] for the dissolve of pure HA in the buffer.</h3>

When pure HA is added to the buffer, the buffer component ratio and the pH decrease. The added HA increases the concentrations of NA and HA. However, there is a greater relative increase in the concentration of HA. Hence, the ratio of [NaA]/[HA] decreases, causing the solution to become more acidic.

The capacity of a buffer to withstand pH change is measured. The concentration of the buffer's components namely, the acid and its conjugate base determine this ability. Greater buffer capacity is associated with higher buffer concentration.

To learn more about buffer-component, Visit:

brainly.com/question/9542245

#SPJ4

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The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If the
aleksley [76]

Answer:

It will require<u> second round</u> of the cycle to release 14C0_2

Explanation:

<u>Reason behind the requirement of second round of the cycle to release </u>CO_2 -:

The C4 carbon of succinyl CoA is acetyl from acetyl CoA. Succinyl CoA is converted to succinate, which is then converted to fumarate, fumarate, malate, and eventually oxaloacetate. 14C will be found in oxaloacetate at either C1 or C4. During the second round of the loop, each of these carbons will be converted to carbon dioxide.

7 0
3 years ago
Explain the difference between fixed and variable oxidation
dem82 [27]

Fixed vs Variable Oxidation is given below.

Explanation:

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A variable oxidation state is a value that determines the charge of the atom depending on certain conditions.

2. Ox­i­da­tion state of el­e­ments is con­sid­ered to be of the most im­por­tant in the study of chem­istry. For some el­e­ments, this fig­ure is con­stant known as fixed oxidation , while for oth­ers it is vari­able is called variable oxidation state.

3. MgCl2 :  magnesium is in Group IIA and all elements in Group IIA have fixed oxidation numbers of +2

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7 0
3 years ago
What would be the pH of a solution of a solution with a hydrogen ion concentration of 0.001 M?
son4ous [18]

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7 0
3 years ago
100 POINTS ANSWER FAST
alex41 [277]
I believe the answer is a because 2 times 12 is 24. Hope this helped
8 0
4 years ago
Read 2 more answers
Write the isotopic symbol for the following (show your work) a) An isotope of iodine whose atoms have 78 neutrons b) An isotope
morpeh [17]

<u>Answer:</u>

<u>For a:</u> The isotopic representation of iodine is _{53}^{131}\textrm{I}

<u>For b:</u> The isotopic representation of cesium is _{55}^{137}\textrm{Cs}

<u>For c:</u> The isotopic representation of strontium is _{38}^{52}\textrm{Sr}

<u>Explanation:</u>

The isotopic representation of an atom is: _Z^A\textrm{X}

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

  • <u>For a:</u>

We are given:

Number of neutrons = 78

Atomic number of iodine = 53 = Number of protons

Mass number = 53 + 78 = 131

Thus, the isotopic representation of iodine is _{53}^{131}\textrm{I}

  • <u>For b:</u>

We are given:

Number of neutrons = 82

Atomic number of cesium = 55 = Number of protons

Mass number = 55 + 82 = 137

Thus, the isotopic representation of cesium is _{55}^{137}\textrm{Cs}

  • <u>For c:</u>

We are given:

Number of neutrons = 52

Atomic number of strontium = 38 = Number of protons

Mass number = 38 + 52 = 90

Thus, the isotopic representation of strontium is _{38}^{52}\textrm{Sr}

3 0
3 years ago
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