Answer:
280.8 g
Explanation:
Definimos la reaccion:
2NaOH + FeSO₄ → Na₂SO₄ + Fe(OH)₂
Como tenemos la masa de NaOH, asumimos que el sulfato de hierro (II) es el reactivo en exceso.
Definimos masa de reactivo: 250 g . 1mol / 40g = 6.25 mol
2 moles de NaOH producen 1 mol de hidroxido ferroso
Entonces 6.25 moles producirán, la mitad (6.25 . 1) /2 = 3.125 moles
Convertimos los moles a masa:
3.125 mol . 89.85 g/mol = 280.8 g
Answer:
36.66%
Explanation:
Step 1: Given data
- Mass of the sample: 2.875 g
Step 2: Calculate the mass of salt
The mass of the sample is equal to the sum of the masses of the components.
m(sample) = m(iron) + m(sand) + m(salt)
m(salt) = m(sample) - m(iron) - m(sand)
m(salt) = 2.875 g - 0.660 g - 1.161 g
m(salt) = 1.054 g
Step 3: Calculate the percent of salt in the sample
We will use the following expression.
%(salt) = m(salt) / m(sample) × 100%
%(salt) = 1.054 g / 2.875 g × 100% = 36.66%
The type of energy used is kinetic energy. Kinetic energy is the energy of motion.
The time of day the plants are watered is the independent variable. Keera did everything else the same for each plant.
Answer:
The answer is: Hydrolysis
Explanation:
Hydrolysis is the chemical method in which water molecule is added to a molecule, which leads to the cleavage of one or more chemical bonds in the molecule. In this reaction, the water molecule acts as a nucleophile and breaks down the large molecules like polymers into smaller molecules such as monomers. Hydrolysis reaction includes fragmentation, elimination substitution reactions.
