From the chemical equation given:
H2SO4+2KOH--->K2SO4+2H2O
the two reactants, H2SO4 and KOH, are in 1:2 stoichiometric ratio.
No. of moles of KOH = 2* no. of moles of H2SO4
=2*0.1*0.033
The concentration of KOH = no. of moles / volume
=2*0.1*0.033/0.05
=0.132M
Answer:
Ag has atomic number 47 = 47 protons and 47 electrons. mass number is 108, neutrons = 108 - 47 protons = 61 neutrons.
Explanation:
For answering for the question, there exists four choices:
1) Na+ + e- -------------- Na
2) Na --------Na+ + e-
3) Cl2 + 2e- ------------ Cl-
4) 2Cl- ---------Cl2 + 2e-
reduction half-reaction general formula is
oxidant + e - or + -------- Product
so in our case the answer is
1) Na+ + e- -------------- Na (exactly balanced)
C
Because I am right
God bless
