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ivanzaharov [21]
3 years ago
9

Which statement describes the focus of an earthquake?

Chemistry
2 answers:
Arturiano [62]3 years ago
8 0

Answer:

B is the correct answer hope it helps

il63 [147K]3 years ago
6 0

Answer:Its B the person above me is correct go thank and rate 5 there answer!

Explanation:

Hope it helps!

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How many moles of chlorine gas are in 1.2m^3 at room temperature and pressure?
marshall27 [118]

Answer:

look it up lol

Explanation:

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3 years ago
What is called exothermic ​
Jobisdone [24]

An exothermic process is one that gives off heat.

Explanation:

This heat is transferred to the surroundings. An endothermic process is one in which heat has to be supplied to the system from the surroundings.

4 0
2 years ago
The orderly geometric arrangement of atoms is called a crystalline solid. <br> a. True<br> b. False
Crank
a.True.

The ordely geometric arrangement of atmos is called a crystalline solid.
4 0
3 years ago
Read 2 more answers
For the following reaction, identify whether the compound in bold is behaving as an acid or a base.
harina [27]

Answer: acid

Explanation: it dissolves in water to produce hydronium ion as the only positive ion

3 0
3 years ago
If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was
Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

n_{acid}=n_{base}=n_{salt}

Whereas the moles of the salt are computed as shown below:

n_{salt}=0.021L*0.68mol/L=0.01428mol

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

[salt]=0.01428mol/0.0276L=0.517M

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

C_6H_5NH_3^++H_2O\rightleftharpoons  C_6H_5NH_2+H_3O^+

Whose equilibrium expression is:

Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

2.326x10^{-5}=\frac{x^2}{0.517M}

Whereas x is:

x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

pH=-log(3.47x10^{-3})\\\\pH=2.46

Regards!

6 0
3 years ago
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