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qaws [65]
3 years ago
11

A few pieces of dry ice, CO2(s), at -78°C are placed in a flask that contains air at 21°C. The flask is sealed by placing an uni

nflated balloon over the mouth of the flask. As the balloon inflates, the dry ice disappears and no liquid is observed in the flask.
State the direction of heat flow that occurs between the dry ice and the air in the flask.
Write the name of the process that occurs as the dry ice undergoes a phase change in the flask. [1]
Compare the entropy of the CO2 molecules in the dry ice to the entropy of the CO2 molecules in the inflated balloon.
Chemistry
2 answers:
arsen [322]3 years ago
8 0
The direction of heat flow is from surroundings to system (air to ice), the dry ice is subliminating.
7nadin3 [17]3 years ago
4 0

Answer:

  • Heat flows from the air into the dry ice.
  • Sublimation (its when a solid becomes a gas without becoming a liquid first).
  • CO2 molecules in gaseous phse has more entropy than in solid phase.

Explanation:

  • To sublimate dry ice needs to fain energy, wich is provided by the surrounding air.
  • Solid is the more condensated state of matter, so it has less entropy than any other state of matter.
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A grating has 470 lines/mm. how many orders of the visible wavelength 538 nm can it produce in addition to the m = 0 order?
maria [59]

Three complete orders on each side of the m=0 order can be produced in addition to the m = 0 order.

The ruling separation is

d=1 / (470mm −1) = 2.1×10⁻³ mm

Diffraction lines occur at angles θ such that dsinθ=mλ, where λ is the wavelength and m is an integer.

Notice that for a given order, the line associated with a long wavelength is produced at a greater angle than the line associated with a shorter wavelength.

We take λ to be the longest wavelength in the visible spectrum (538nm) and find the greatest integer value of m such that θ is less than 90°.

That is, find the greatest integer value of m for which mλ<d.

since  d / λ = 538×10⁻⁹m / 2.1×10 −6 m ≈ 3

that value is m=3.

There are three complete orders on each side of the m=0 order.

The second and third orders overlap.

Learn more about diffraction here : brainly.com/question/16749356

#SPJ4

7 0
1 year ago
In one of his experiments, Lavoisier placed 10.0 grams of mercury (II) oxide into a sealed container and heated it. The mercury
inysia [295]

Oxygen gas produced : 0.7 g

<h3>Further explanation</h3>

Given

10.0 grams HgO

9.3 grams Hg

Required

Oxygen gas produced

Solution

Reaction⇒Decomposition

2HgO(s)⇒2Hg(l)+O₂(g)

Conservation of mass applies to a closed system, where the masses before and after the reaction are the same

mass of reactants = mass of products

mass  HgO = mass Hg + mass O₂

10 g = 9.3 g + mass O₂

mass O₂ = 0.7 g

4 0
3 years ago
Draw the Lewis structure for the Se and 2 H atoms.
fomenos
When  drawing lewis dot  diagram  structure  we  consider the  number  of  valence electrons  of  the atom.Se  has  six valence electrons since  it  is  in  group  six thus  it Lewis  dot diagram  is  as  follows
       ..
     : Se:
Hydrogen  is  in  group  one  hence  has  one  valence  electron.The  lewis dot  diagram  for  2H is  therefore
        H:H
3 0
3 years ago
Read 2 more answers
If you have 222 g of radioisotope with a half-life of 5 days, how much isotope would remain after 15 days?
Dima020 [189]
If the half life is 5 days, you would have to divide 222 by 2 3 times.
so 222/2 =111g
111/2 = 55.5g
55.5/2 = 27.75g

after four half life the mass would be
27.75/2
13.875g

the percent would be
13.875/222
= 6.25%
7 0
3 years ago
When the following equation is balanced, the coefficients are ________.
LuckyWell [14K]

Answer:

B

Explanation:

Option B is the correct answer. When you add 7 in front of the O2 in the left side, and then you add 4 and 6 in front of NO2 and H2O respectively, the number of oxygen atoms is the same in both sides.

4 0
2 years ago
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