Outcome on winning = $100 - $20 = $80
Outcome on losing = $20
Probability of winning = 1/6
Probability of losing = 5/6
Expected Value = 1/6 (80) +5/6(-20) = -3.333
This shows on average from each game, the game earns $ 3.333.
So, if 1000 such games are played, the game will earn 1000 x 3.33 = $3330
So, the answer to this question is option A
Answer:
<em>Answer: A. 0.2</em>
Step-by-step explanation:
<u>Probability</u>
The circle graph shows the distribution of the makeup of the Riverside Municipal Choir.
The total number of choir sections is: 8+10+10+12=40
To calculate the probability of a member chosen at random comes from the alto section, we use the formula:

Calculating:
P = 0.2
Answer: A. 0.2
apple pies are like rectangles u take how many apple chunks times the amount of cooking times but u have no answer
Answer:
.
Step-by-step explanation:
Given:
In Right Angle Triangle GIH
∠ I = 90°
GI = 7 ....Side opposite to angle H
GH = 10 .... Hypotenuse
To Find:
m∠H = ?
Solution:
In Right Angle Triangle ABC ,Sine Identity,

Substituting the values we get;

Now taking
we get;

rounding to nearest tenth we get.
.
Hence
.
Answer:
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So
X = 8.6



has a pvalue of 0.8413
X = 6.4



has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds