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saw5 [17]
3 years ago
15

Fraction between 13/10 and 7/5

Mathematics
1 answer:
IrinaK [193]3 years ago
3 0
Add 13/10 plus 7/5 to get 27/10
or you could make it 2 7/10
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Evaluate -2x^3-3x^2+4 for x=-2
dsp73

Answer: 8

Step-by-step explanation:

1. Rewrite the equation:

-2x^3 - 3x^2 + 4     x = -2

2. Plug in the value of x, -2

-2(-2)^3 - 3(-2)^2 + 4

3. Use order of operations (PEMDAS):

-2(-8) - 3(4) + 4

= 16 - 12 + 4

= 8

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%3D-4x%5E%7B2%7D%2B5x" id="TexFormula1" title="f(x)=-4x^{2}+5x" alt="f(x)=-4x^{2}+5x"
JulijaS [17]

Answer:

Domain= (-inf,inf)/(-∞,∞)

Range= (-inf,25/16]

x-intercepts= (0,0), (5/4,0)

y-intercepts=(0,0)

vertex= maximum (5/8,25/16)

8 0
2 years ago
Last year. Samara practiced playing the violin for 26 hours the piano for 35 hours, the flute for 41 hours, and the drums for 18
vova2212 [387]

Answer:

5 days

Step-by-step explanation:

26+35+41+ 18 = 120

120/24 = 5

3 0
2 years ago
What is : 65=4u+13 ????
Rus_ich [418]

Answer: 13


Step-by-step explanation:

65-13=54

54/4=13

Order of operations

6 0
3 years ago
Read 2 more answers
A chestnut falls out of a tree 45 feet above the ground. Use the vertical motion model, H=-16t^2+vt+s s to find how long it take
valentinak56 [21]

Answer:

1.7 seconds

Step-by-step explanation:

we have

H=-16t^2+vt+s

where

v is the initial velocity (in feet per second)

s represents the initial height (in feet)

In this problem we have

v=0 ---> because the object is dropped

s=45\ ft

substitute

H=-16t^2+45

Remember that

When the chestnut hit the ground the value of H is equal to zero

so

For H=0

-16t^2+45=0

solve for t

16t^2=45\\t^2=2.8125\\t=\pm1.7\ sec

therefore

The solution is t=1.7 sec

7 0
2 years ago
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