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erastova [34]
2 years ago
11

E-1, e-2 and e-3 are three engineering students writing their assignments at night. Each of them starts at a different time and

completes at a different time. The digit in their name and the order of their starting and completing the assignment is certainly not the same. The last student to start is the first to complete the assignment. Who is the first student to start writing the assignment?.
Mathematics
1 answer:
Bas_tet [7]2 years ago
8 0

E-3 will be the first student to start writing the assignment.

It is clearly stated in the statement that the order of starting the assignment and the order of the completion of the assignment is not the same, the digit in the name of the executive is also not same. This information puts some restrictions.

E-1 can neither be the first one to start nor the first one to complete. Similarly, E-2 cannot be the second one and E-3 cannot be the third one.

It is given that the last student (the third one) to start is the first student (the first one) to complete. This can neither be E-3 nor E-1. It is E-2

The final arrangement is as follows.

                                 Start           Complete

First                           E-3              E-2

Second                      E-1               E-3

Third                          E-2              E-1

E-3 is the first one to start writing the assignment.

More similar problems are solved in the link.

brainly.com/question/28391619?referrer=searchResults

#SPJ4

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Hi there! The answer is C.

The area of the square in the middle is the following:
length \: \times \: width \: = 5 \times 5 = 25
Hence, the area of the square is 25 cm^2.

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The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

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Answer:

The inverse of function f(x)= (x+7)^5 is \mathbf{f^{-1} (x)=\sqrt[5]{x}+7}

Option A is correct option.

Step-by-step explanation:

For the function f(x)= (x+7)^5, Find f^{-1} (x)

For finding inverse of x,

First let:

y=(x+7)^5

Now replace x with y and y with x

x=(y+7)^5

Now, solve for y

Taking 5th square root on both sides

\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7

Now, replace y with f^{-1} (x)

f^{-1} (x)=\sqrt[5]{x}+7

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Option A is correct option.

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