The concentration of the HCL in the mixed solution is 32%
Considering the First solution containing HCl,
80 ml of 50% = 80 x (50/100)
= 80 x 0.5
= 40 ml of HCL
Considering the second solution containing HCl,
120 ml of 80% = 120 x (20/100)
= 120 x 0.2
= 24 ml of HCl
So, the combined solution will have = 40+ 24
= 64 ml of HCL
Since the combined volume of the two solutions was = 80+120
= 200 ml
As for finding the concentration of HCl in a solution, the required formula is to divide the volume of HCl by the combined volution of the solution.
Therefore, the concentration of HCl will be = 64/200
= 0.32
Which is 32% of HCl
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