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2 years ago

What volume of a 2.10 M NaCl solution is

Chemistry

1 answer:

cluponka [151]2 years ago

3 0

Answer:

146.3g NaCl (mol NaCl/58.44g NaCl) = 2.50 mol NaCl

1.5M NaCl = 1.5 mol NaCl / 1 L = 2.5 mol NaCl / x L, solve for x

x L = 2.5 mol NaCl / 1.5 mol NaCl = 1.66 L

It gives the answer and all the working.

To put it another way:

Dividing the amount required by the molar mass

we quickly see that 2.5 moles are required.

One litre of 1.5 molar solution gives 1.5 moles

we need a further mole, which is 2/3 of 1.5 so 2/3 of a litre.

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A medication 60 mg is ordered. the vial is labeled 1 gm/ 10 ml. How many ml would you give?

timofeeve [1]

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3 years ago

True or false? When sodium and chlorine combine and bond, a molecule is formed.

CaHeK987 [17]

When Sodium and Chlorine come together they transfer an electron.

- Source: google

Hopefully this was clear and you understood!

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2 years ago

What are the radicals?Write their types with four examples.

polet [3.4K]

Answer:

<h3>A group of atoms behaving as a unit in a number of compounds. </h3>

Explanation:

<h2>Sorry for giving half answer only .I known this much only.</h2><h2>I hope U like my answer and my answer help u.</h2>

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2 years ago

Read 2 more answers

An electron in the hydrogen atom makes a transition from an energy state of principal quantum number ni to the n = 2 state. If t

topjm [15]

Answer:

$\boxed{3}$

Explanation:

The Rydberg equation gives the wavelength λ for the transitions:

$\dfrac{1}{\lambda} = R \left ( \dfrac{1}{n_{i}^{2}} - \dfrac{1}{n_{f}^{2}} \right )$

where

R= the Rydberg constant (1.0974 ×10⁷ m⁻¹) and

$\text{$n_{i}$ and $n_{f}$ are the numbers of the energy levels}$

Data:

$n_{f} = 2$

λ = 657 nm

Calculation:

$\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}$

7 0

2 years ago

group of atoms that gains or loses electrons is called _______. A. a polar ion B. a non-polar ion C. a polyatomic ion D. a commo

raketka [301]

Answer: Option (C) is the correct answer.

Explanation:

An ion is defined as a specie which is formed when a neutral atoms tends to gain or lose an electron.

When a neutral atom gain an electron then it forms a negative ion whereas when a neutral atom tends to lose an electron then it forms a positive ion.

For example, a neutral fluorine atom on gaining an electron will form $F^{-}$ ion. And, a sodium atom on losing an electron forms $Na^{+}$ ion.

When a group of atoms form ions then it tends to form polyatomic ions.

Thus, we can conclude that group of atoms that gains or loses electrons is called a polyatomic ion.

7 0

2 years ago