Period 4 transition element that forms 2+ ion with a half‐filled d sub level is
Manganese (Mn)
What is the half-filled d sub-level?
Transition metals are an interesting and challenging group of elements. They have perplexing patterns of electron distribution that don’t always follow the electron-filling rules. Predicting how they will form ions is also not always obvious.
Transition metals belong to the d block, meaning that the d sublevel of electrons is in the process of being filled with up to ten electrons. Many transition metals cannot lose enough electrons to attain a noble-gas electron configuration. In addition, the majority of transition metals are capable of adopting ions with different charges. Iron, which forms either the Fe2+ or Fe3+ ions, loses electrons as shown below.
Some transition metals that have relatively few d electrons may attain a noble-gas electron configuration. Scandium is an example. Others may attain configurations with a full d sublevel, such as zinc and copper.
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Variations in the solar resource are probably the first and main consideration. You can use local weather stations where available, otherwise satellite data (eg from NASA's website) or commercial databases such as Meteonorm. Also there is quite a comprehensive set of data files in the SAM software
Other important considerations are
local environment: plants and animals that could be affected by the system; community support and buy-in.wind, hail, rain, snow profile for the location in question. if there are high/tropical winds then it will increase the plant cost.flight paths and roads near the plant which could be affected by glint and glareproximity to a local town where staff will be able to live both during construction and later during operationproximity to a electricity transmission line with available capacityavailability of water for mirror cleaning and steam blowdown.cost (and availability) of electricity in the area. If remote, electricity/energy may be very expensive, which will enable a high price for electricity sold from the plant.quality of road to the plant, required to bring equipment and materials to sitepolitical stability of the region -- potential impact on perceived bankability of the project.
Many of these items will have a large influence on the cost of the plant and/or the revenue it will generate during its life. Others relate to environmental and risk factors and are also critically important to consider.
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Answer:
The answer is 0.36 kg/s NO
Explanation:
the chemical reaction of NH3 to NO is as follows:
4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l)
We have the following data:
O2 Volume rate = 645 L/s
P = 0.88 atm
T = 195°C + 273 = 468 K
NO molecular weight = 30.01 g/mol
we calculate the moles found in 645 L of O2:
P*V = n*R*T
n = P*V/R*T
n= (0.88 atm * 645L/s)/((0.08205 L*atm/K*mol) * 468 K) = 14.78 moles of O2
With the reaction we can calculate the number of moles of NO and with its molecular weight we will have the rate of NO:
14.78 moles/s O2 * 4 molesNO/5 molesO2 * 30.01 g NO/1 molNO x 1 kgNO/1000 gNO = 0.36 kg/s NO
Answer:
5400 cans
Explanation:
First we convert the total weight, 1 ton, to grams:
Now we need to know the mass of aluminum:
Now we make the relation between the mass of aluminum in 1 ton of the earth's crust and the mass of aluminum per can:
Answer:go read ur book and u will find it!!
Explanation:
