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irinina [24]
2 years ago
3

Are these statements true or false? Correct any false ones.

Chemistry
1 answer:
Alex17521 [72]2 years ago
7 0

This is true statement. Reason : As s orbitals have a spherical shape, only sigma bonds are possible from bonds formed by s orbitals.

<h3>Do 2 sigma bonds comprise a double bond?</h3>

In general, single bonds between atoms are always sigma bonds. Double bonds are comprised of one sigma and one pi bond.

Triple bonds are comprised of one sigma bond and two pi bonds.

<h3>How many sigma and pi bonds are present in triple bond?</h3>

A triple bond consists of two pi bonds and one sigma bond.

A double bond contains one sigma and one pi bond. Single bonds are always sigma bonds.

Learn more about sigma bond here:

<h3>brainly.com/question/10123266</h3><h3 /><h3>#SPJ4</h3>
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A 0.98 M solution of calcium chloride with a volume of 0.25 L is diluted to form a 0.74 M solution. What is the new volume of th
tankabanditka [31]

The new volume of the dilute solution is 0.33 L.

<u>Explanation:</u>

Using the law of Volumetric analysis, we can find the volume of the dilute solution from the stock solution or the concentrated solution of Calcium Chloride.

V1M1 = V2M2

V1 be the volume of the stock solution = 0.25 L

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M2 being the molarity of the dilute solution = 0.74 M

We have to rearrange the above equation to find V2 as,

V2 = $\frac{V1M1}{M2}

Now plugin the values as,

V2 = $\frac{0.25 L \times 0.98 M }{0.74 M}

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3 years ago
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Answer:

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Explanation:

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elena-s [515]

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b) Oxygen and strontium : SrO :  strontium oxide.

c) Aluminum and chlorine : AlCl_3  : aluminium chloride.

d) Cesium and bromine : CsBr  : cesium bromide.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

a) Sodium and nitrogen : Here sodium is having an oxidation state of +1 called as Na^{+} cation and nitrogen forms an anion N^{3-} with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral NaN_3  named as sodium nitride.

b) Oxygen and strontium : Here strontium is having an oxidation state of +2 called as Sr^{+} cation and oxygen forms an anion O^{2-} with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral SrO  named as strontium oxide.

c) Aluminum and chlorine : Here aluminium is having an oxidation state of +3 called as Al^{3+} cation and chlorine forms an anion Cl^{-} with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral AlCl_3  named as aluminium chloride.

d) Cesium and bromine : Here cesium is having an oxidation state of +1 called as Cs^{+} cation and bromine forms an anion Br^{-} with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral CsBr  named as cesium bromide.

7 0
3 years ago
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Hoochie [10]

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