Answer:
a. 599 cm³
b. 1.49 g/cm³
Explanation:
<h3>A. Volume </h3>
Volume is the amount of space an object occupies. Since this is a brick, the object is a rectangular prism. The formula for the volume of a rectangular prism is the product of length, width, and height.
The brick's length (l) is 13.77 centimeters, the width (w) is 8.50 centimeters, and the height (h) is 5.12 centimeters. Substitute these values into the formula.
Multiply the numbers together.
The original measurements have at least 3 significant figures, so our answer must have 3. For the number we calculated, that is the ones place. The 2 in the tenths place tells us to leave the 9 in the ones place.
<h3>2. Density </h3>
Density is the amount of matter in a specified space. The formula for density is mass over volume.
The mass of the brick is 895.3 grams and we just found the volume to be 599.2704 cubic centimeters. Substitute the values into the formula.
Divide.
Round to three significant figures. For the number we calculated, that is the hundredth place. The 4 in the thousandth place tells us to leave the 9 in the hundredth place.
Answer:
its Sio2 that is your anwser also this is usless so dont submit it
Explanation:
<h3>
Answer:</h3>
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
6.022 × 10²² atoms Fe (iron)
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
- Divide:
If I did this correctly the balanced equation would be:
14H⁺+Cr₂O₇²⁻+6I⁻→3I₂+2Cr³⁺+7H₂O
oxidation half: (iodide was oxidized)
2I⁻→I₂+2e⁻
reduction half: (chromium was reduced)
14H⁺+Cr₂O₇²⁻+6e⁻→2Cr³⁺+7H₂O
H⁺ comes from the solution. It is in the final reaction since in redox reactions the oxygen is turned into water since it can't just go away. I multiplied the oxidation half reaction by 3 in order for both half reactions to half the same number of electrons since equal numbers of electrons need to be lost and gained for the reaction to be balanced.
I hope this helps. Let me know if anything is unclear.
Answer:
wwe are asked to prive the atomic pavking factor APF for BCC is 0.68
solution
APF is given by equation (3.3) in the form
APF =nVs/Vc
whenn is the number of atoms per unit cell and for BCC n=2.0, Vs is the volume of the atom and it is given by 43π3³ and Vc is the volume of the unit cell and for BCC Vc=a³ where a is the side of the cube. From equation 3.4
we could get a by
a=4R/√3
where R is the radius of the atom. Now let us olug the expression inyo equation (1) to get APF
APF = nVs/Vc
=2.0(4/3πR³) / (4R/√3)³
=2.0(4/3πR³) / (4/√3)³ R³
=0.68