Answer:
In this conditions, the gaswll weight 46.74 g.
Explanation:
The idal gas law states that:
PV = nRT,
P: pressure = 740 mmHg = 0.97 atm
V: volume = 14.5 L
n: number of moles
R: gas constant =0.08205 L.atm/mol.K
T: temperature = 29°C = 302.15K
1 mol gas ___ 82 g
0.57 mol gas __ x
x = 46.74 g
It depends on the function and activity of both cells. Most normal cells crease division if they came into contact with other cells however the immune system interact directly with pathogens or foreign organisms to destroy them.
The molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.
<h3>HOW TO CALCULATE MOLAR CONCENTRATION:</h3>
- The molar concentration of a solution can be calculated by dividing the number of moles by its volume.
- According to this question, there are 469 grams of C6H12O6 in 82 milliliters of water.
The number of moles = 469g ÷ 180.156g/mol = 2.6mol
Volume of water in litres = 82/1000 = 0.082L
Concentration of solution = 2.6mol ÷ 0.082L = 31.71M
Therefore, the molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.
Learn more about concentration at: brainly.com/question/202460
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