Question

A 500.0 g block of dry ice (solid CO2, molar mass = 44.0 g) vaporizes at room temperature. Calculate the volume of gas produced at 25.0 °C and 1.50 atm.

Answer 1

Considering the ideal gas law, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

Definition of ideal gas

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

Ideal gas law

An ideal gas is characterized by absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

Volume of gas

In this case, you know:

• P= 1.50 atm
• V= ?
• n= 500 g×$\frac{1 mole}{44 g}$= 11.36 moles, being 44 $\frac{g}{mole}$ the molar mass of CO₂
• R= 0.082 $\frac{atmL}{molK}$
• T= 25 C= 298 K (being 0 C=273 K)

Replacing in the ideal gas law:

1.50 atm×V = 11.36 moles×0.082$\frac{atmL}{molK}$ × 298 K

Solving:

V= (11.36 moles×0.082$\frac{atmL}{molK}$ × 298 K) ÷ 1.50 atm

V= 184.899 L

Finally, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

Learn more about the ideal gas law:

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