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il63 [147K]
2 years ago
7

How many grams are in 3.14 x 1015 molecules of CO?

Chemistry
1 answer:
Vesnalui [34]2 years ago
5 0

Answer:

Explanation:

Not Many

1 mol of CO has a mass of

C = 12

O = 16

1 mol = 28 grams.

1 mol of molecules = 6.02 * 10^23

x mol of molecules = 3.14 * 10^15        Cross multiply

6.02*10^23 x = 1 * 3.14 * 10^15             Divide by 6.02*10^23

x = 3.14*10^15 / 6.02*10^23

x = 0.000000005 mols

x = 5*10^-9

1 mol of CO has a mass of 28

5*10^-9 mol of CO has a mass of x                        Cross Multiply

x = 5 * 10^-9 * 28

x = 1.46 * 10^-7 grams

Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample

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Answer:

B

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...which isn't actually an option because none of them have decimal points but I would say it is B anyway because it is the equivalent ratio and maybe there was a typo.

Hope this helped!

6 0
3 years ago
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gavmur [86]

Answer:

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Solution:

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7 0
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I think the one that cause the equilibrium to shift would be :
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3 0
3 years ago
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kirza4 [7]

Answer:

Explanation:

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2 years ago
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ahrayia [7]

Answer:

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