Answer:
The answer to your question is it is not at equilibrium, it will move to the products.
Explanation:
Data
Keq = 2400
Volume = 1 L
moles of NO = 0.024
moles of N₂ = 2
moles of O₂ = 2.6
Process
1.- Determine the concentration of reactants and products
[NO] = 0.024 / 1 = 0.024
[N₂] = 2/1 = 2
[O₂] = 2.6/ 1= 2.6
2.- Balanced chemical reaction
N₂ + O₂ ⇒ 2NO
3.- Write the equation for the equilibrium of this reaction
Keq = [NO]²/[N₂][O₂]
- Substitution
Keq = [0.024]² / [2][2.6]
-Simplification
Keq = 0.000576 / 5.2
-Result
Keq = 1.11 x 10⁻⁴
Conclusion
It is not at equilibrium, it will move to the products because the experimental Keq was lower than the Keq theoretical-
1.11 x 10⁻⁴ < 2400
Half-life time of a reaction is time at which reactant concentration becomes half of its initial value.
Half-life of the first order reaction is 20 min. Rate constant can be calculated as follows:
![K=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{20 min}=0.03466 min^{-1}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B0.6932%7D%7Bt_%7B1%2F2%7D%7D%3D%5Cfrac%7B0.6932%7D%7B20%20min%7D%3D0.03466%20min%5E%7B-1%7D)
The rate expression for first order reaction is as follows:
![k=\frac{2.303}{t}log\frac{A_{0}}{A_{t}}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7Dlog%5Cfrac%7BA_%7B0%7D%7D%7BA_%7Bt%7D%7D)
initial number of molecules of reactant are
, time is 100 min thus, putting the values to calculate number of reactant at time 100 min,
![0.03466 min^{-1}=\frac{2.303}{100 min}log\frac{[10^{20}]}{A_{t}}](https://tex.z-dn.net/?f=0.03466%20min%5E%7B-1%7D%3D%5Cfrac%7B2.303%7D%7B100%20min%7Dlog%5Cfrac%7B%5B10%5E%7B20%7D%5D%7D%7BA_%7Bt%7D%7D)
On rearranging,
![\frac{10^{20}}{A_{t}}=31.988](https://tex.z-dn.net/?f=%5Cfrac%7B10%5E%7B20%7D%7D%7BA_%7Bt%7D%7D%3D31.988)
Or,
![A_{t}=3.13\times 10^{18}](https://tex.z-dn.net/?f=A_%7Bt%7D%3D3.13%5Ctimes%2010%5E%7B18%7D)
Therefore, number of molecules unreacted will be ![3.13\times 10^{18}](https://tex.z-dn.net/?f=3.13%5Ctimes%2010%5E%7B18%7D)
Answer: ≈ 0.833 atm
Explanation:
2.5 / 60 = 20 / P
In order to solve for P, we must find divide 2.5 by 60 which gives us 0.04167. Then we multiply by 20 to get 0.833 atm
Covalent, as Isopentene (2 methylbutane) is completely non-metallic
Answer:
In this excerpt, Emerson is in favor of, and stresses the importance of, individual intellect and moral development. He urges readers to look within—into their inner selves to seek inspiration and attain self-reliance rather than imitating others or adopting age-old ideas, which society has practiced over time. He uses examples of great thinkers such as Moses, Milton, and Plato, who thought for themselves and didn’t let society and established ideas influence them. Emerson further stresses that people should not dismiss their own ideas, only to discover them in others’ works, but learn to nurture and accept their potential. When people are able to accept and trust their own thoughts, they will be able to come up with ideas as brilliant and original as those of any wise man.
Explanation:
Hope this helps.