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Katena32 [7]
3 years ago
13

If 15 drops of ethanol from a medical dropper weight 0.60g, how many drops does it takes from a dropper to dispense 1.0ml of eth

anol? The density of ethanol is 0.80g/ml
Chemistry
1 answer:
Hoochie [10]3 years ago
8 0

Answer : The number of drops it takes from a dropper to dispense 1.0 ml of ethanol is, 20 drops

Solution : Given,

Density of ethanol = 0.80 g/ml

Mass of ethanol = 0.60 g

First we have to calculate the volume of ethanol.

Formula used : Density=\frac{Mass}{Volume}

0.80g/ml=\frac{0.60g}{Volume}

Volume=\frac{0.60g}{0.80g/ml}=0.75ml

The volume of ethanol is, 0.75 ml

Now we have to calculate the number of drops it takes from a dropper to dispense 1 ml of ethanol.

As, the number of drops in 0.75 ml of ethanol = 15

So, the number of drops in 1.0 ml of ethanol = \frac{15}{0.75}\times 1.0=20

Therefore, the number of drops it takes from a dropper to dispense 1.0 ml of ethanol is, 20 drops

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Convert 7.89 x 10^8 molecules of water to liters.
NNADVOKAT [17]

Answer:

2.94 x 10⁻¹⁴L

Explanation:

To solve this problem, we have to assume that the condition of this water is at standard temperature and pressure, STP.

At STP;

       1 mole of gas have a volume of 22.4L

So, let us find the number of moles of this water first;

         6.02 x 10²³ molecules can be found in 1 mole of a substance

          7.89 x 10⁸ molecules will contain \frac{7.89 x 10^{8} }{6.02 x 10^{23} }   = 1.31 x 10⁻¹⁵mole of water

So;

        Volume of water  = 22.4 x 1.31 x 10⁻¹⁵  = 2.94 x 10⁻¹⁴L

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3 years ago
Joan wants to test if salt lowers the temperature at which water boils. In two or more complete sentences, describe the best way
Alexeev081 [22]
Put a thermometer in the water and wait until it boils. When it boils record the temperature and compare it to the normal water boiling point.
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3 years ago
How many grams of Fe will be produced if 705.0g of H20 are produced?
fredd [130]
<h3>Answer:</h3>

2265 g Fe₃O₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] Fe₃O₄ + 4H₂ → 3Fe + 4H₂O

[Given] 705.0 g H₂O

<u>Step 2: Identify Conversions</u>

[RxN] 4 mol H₂O → 1 mol Fe₃O₄

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Fe - 55.85 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Molar Mass of Fe₃O₄ - 3(55.85) + 4(16.00) = 231.55 g/mol

<u>Step 3: Convert</u>

  1. Set up stoich:                              \displaystyle 705.0 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{1 \ mol \ Fe_3O_4}{4 \ mol \ H_2O})(\frac{231.55 \ g \ Fe_3O_4}{1 \ mol \ Fe_3O_4})
  2. Multiply/Divide/Cancel units:                                                                           \displaystyle 2264.74 \ g \ Fe_3O_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 4 sig figs.</em>

2264.74 g Fe₃O₄ ≈ 2265 g Fe₃O₄

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The formula for determining the moles of a compound is grams (g) divided by molecular weight (MW), or moles = g / MW. The molecular formula of oxygen gas is O₂, and because each oxygen atom possesses an atomic weight of 16.00 grams per mole (g/mol) (this value is found on the Periodic Table), the MW of oxygen gas is 32.00 g/mol. Therefore, 32 g of oxygen gas represent (32 g) / (32.00 g/mol) = 1.0 moles of O₂.<span>Source(s):
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<em>that the relative atomic mass of the middle element in each triad was close to the average of the relative atomic masses of the other two elements.</em>

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