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Nookie1986 [14]
3 years ago
10

Elements with atomic numbers of 104 and greater are known as super-heavy elements. None of these elements have been found in nat

ure but instead have been made in a laboratory. They are very difficult and expensive to create, and they break down into other elements quickly. There currently are no practical applications for any of these elements. However, some scientists believe that, with further work, they may discover some isotopes of super-heavy elements that are more stable and that could possibly have practical implications. Do you think that scientists should continue to try to create super-heavy elements and expand the periodic table? Explain why or why not.
Chemistry
2 answers:
Lemur [1.5K]3 years ago
8 0

Here we have to justify the work of scientists to generate more unknown elements after atomic number 104 which are so unstable and cannot be obtained in nature.

It is fact that the stability of the super heavy element is hard to obtain, as when there are so much proton  and neutron at the nucleus of such element makes it so unstable.

So the try to make more unknown element to enlarge the periodic table is not justified as per the stability and utility of such elements are concerned. But in fact it helps to get the new elements which may exist and may have some radioactivity which can be used.

But apparently the making of new material in laboratory to expand the periodic table is not justified.  

yan [13]3 years ago
8 0

Answer:

Here we have to justify the work of scientists to generate more unknown elements after atomic number 104 which are so unstable and cannot be obtained in nature. So the try to make more unknown element to enlarge the periodic table is not justified as per the stability and utility of such elements are concerned. But in fact it helps to get the new elements which may exist and may have some radioactivity which can be used.

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<u>Answer:</u>

<u>For a:</u> Lead iodide is a yellow precipitate.

<u>For b:</u> Barium sulfate is a white precipitate.

<u>For c:</u> Ferric hydroxide is a brown precipitate.

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Precipitation reaction is defined as the reaction where a solid precipitate (solid substance) is formed at the end of the reaction. It is insoluble in water.

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The chemical reaction between KI and lead (II) nitrate follows:

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  • <u>For b:</u>

The chemical reaction between barium chloride and sulfuric acid follows:

BaCl_2(aq)+H_2SO_4(aq)\rightarrow BaSO_4(s)+2HCl(aq)

The sulfate of barium is insoluble in water. Thus, barium sulfate is a white precipitate.

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The chemical reaction between NaOH and ferric chloride follows:

3NaOH(aq)+FeCl_3(aq)\rightarrow Fe(OH)_3(s)+3NaCl(aq)

The hydroxide of iron is insoluble in water. Thus, ferric hydroxide is a brown precipitate.

  • <u>For d:</u>

The chemical reaction between NaOH and copper sulfate follows:

CuSO_4+2NaOH\rightarrow Cu(OH)_2+Na_2SO_4

The hydroxide of copper is insoluble in water. Thus, copper (II) hydroxide is a blue precipitate.

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