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Nookie1986 [14]
3 years ago
10

Elements with atomic numbers of 104 and greater are known as super-heavy elements. None of these elements have been found in nat

ure but instead have been made in a laboratory. They are very difficult and expensive to create, and they break down into other elements quickly. There currently are no practical applications for any of these elements. However, some scientists believe that, with further work, they may discover some isotopes of super-heavy elements that are more stable and that could possibly have practical implications. Do you think that scientists should continue to try to create super-heavy elements and expand the periodic table? Explain why or why not.
Chemistry
2 answers:
Lemur [1.5K]3 years ago
8 0

Here we have to justify the work of scientists to generate more unknown elements after atomic number 104 which are so unstable and cannot be obtained in nature.

It is fact that the stability of the super heavy element is hard to obtain, as when there are so much proton  and neutron at the nucleus of such element makes it so unstable.

So the try to make more unknown element to enlarge the periodic table is not justified as per the stability and utility of such elements are concerned. But in fact it helps to get the new elements which may exist and may have some radioactivity which can be used.

But apparently the making of new material in laboratory to expand the periodic table is not justified.  

yan [13]3 years ago
8 0

Answer:

Here we have to justify the work of scientists to generate more unknown elements after atomic number 104 which are so unstable and cannot be obtained in nature. So the try to make more unknown element to enlarge the periodic table is not justified as per the stability and utility of such elements are concerned. But in fact it helps to get the new elements which may exist and may have some radioactivity which can be used.

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For the reaction: 2 H2 + 2 NO → N2 + 2 H2O the observed rate expression, under some conditions, is: rate = k[H2][NO]2 Which of t
Andrew [12]

Answer:

Step 1 H2 + 2 NO → N2O + H2O (slow)

step 2 N2O + H2 → N2 + H2O (fast)

Explanation:

It is known that the slowest step in a reaction is the rate determining step in a sequence of reactions (reaction mechanism).

We have two important pieces of information in the question to guide our decision making process.

The overall reaction equation, and the rate expression. The two;

2 H2 + 2 NO → N2 + 2 H2O and rate = k[H2][NO]2 all support the answer given above.

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3 0
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Carbon-14 has a half-life of 5,730 years. It is used in "carbon dating" to determine the age of once living organisms. How much
Nookie1986 [14]

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18 grams

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Because 17,190 yrs divided by the amount of years it takes for a half-life to occur is 3. So 3 half life’s happen, so you divide 144/2 once, equaling 72. You divide 72/2 again (another half-life) and you get 36. You then calculate the third half life by dividing 36/2 which equals 18 grams.

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According to the following reaction, how many grams of potassium sulfate will be formed upon the complete reaction of 23.8 grams
Alexxandr [17]

<u>Answer:</u> The mass of potassium sulfate that can be produced is 73.88 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For KOH:</u>

Given mass of KOH = 23.8 g

Molar mass of KOH = 56.1 g/mol

Putting values in equation 1, we get:

\text{Moles of KOH}=\frac{23.8g}{56.1g/mol}=0.424mol

The chemical equation for the reaction of KOH and potassium hydrogen sulfate follows:

KHSO_4+KOH\rightarrow K_2SO_4+H_2O

As, potassium hydrogen sulfate is present in excess. It is considered as an excess reagent.

KOH is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of KOH produces 1 mole of potassium sulfate

So, 0.424 moles of KOH will produce = \frac{1}{1}\times 0.424=0.424moles of potassium sulfate

Now, calculating the mass of potassium sulfate from equation 1, we get:

Molar mass of potassium sulfate = 174.26 g/mol

Moles of potassium sulfate = 0.424 moles

Putting values in equation 1, we get:

0.424mol=\frac{\text{Mass of potassium sulfate}}{174.26g/mol}\\\\\text{Mass of potassium sulfate}=(0.424mol\times 174.26g/mol)=73.88g

Hence, the mass of potassium sulfate that can be produced is 73.88 grams

8 0
3 years ago
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