Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

Let us solve for n.





We can also write next terms of our sequence as:

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
Answer:
578 + 48 square inches
Step-by-step explanation:
The computation of the area of the purple band is as follows:
Area of the green square = side^2 = x^ square inches
And, the area of the orange square = side^2
The side would be = = 12 + 12 +x = 24 + x
And, now the area would be = (x + 24)^2
Now the area of the orange band is
= Area of the orange square area of the green square
= (x + 24)^2 - x^2
= x^2 + 24^2 + 48 - x^2
= 578 + 48 square inches
Answer:
<em><u>x=-6, y=-2</u></em>, (As a point) (-6, -2).....The point form is not necessary unless you want to solve the system (of equations) by graphing.
Step-by-step explanation:
By substitution:
x-y=-4 By adding y on both sides,
x=y-4
Now you can substitute x for the expression (y-4)
Plug the (y-4) as x in the other equation.
So -2x+3y=6 becomes
-2(y-4)+3y=6
Now solve:
-2(y-4)+3y=6 distributes out to be
-2y+8+3y=6 Now combining like terms
y+8=6 Subtract 8 on both sides to isolate the variable
<u><em>y=-2</em></u>
Now plug the value -2 in where the y is in any equation (preferably the easier/less complicated one) and solve for x.
So x-y=-4 becomes
x-(-2)=-4
=x+2=-4
=<u><em>x=-6</em></u>
Answer:
The graph of the parent function f(x) = |x| is dashed and the graph of the transformed function g(x) = |x| + k is solid. Use the slider to change the value of k. How does changing the value of k affect the graph? Positive values of k shift the graph . Negative values of k shift the graph .