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2 years ago

PLEASE HELP (100PTS)

Mathematics

1 answer:

Step2247 [10]2 years ago

5 0

Answer:

x = 6

Step-by-step explanation:

• ∠THX and ∠XHV have a common side HX and a common vertex H

This means they are two adjacent angles.

Then

m∠THX + m∠XHV = m∠THV

Then

53 + 12x−9 = 16x + 20

<u>Solving the equation</u>:

53 + 12x−9 = 16x + 20

⇔ (53 − 9) + 12x = 16x + 20

⇔ 44 = 16x - 12x+ 20

⇔ 44 - 20 = 4x

⇔ 24 = 4x

$\Longleftrightarrow x = \frac{24}{4} =6$

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A card is chosen from a random deck, then a month of the year is chosen. Find the probability of getting a face card and June.

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3 years ago

Suppose that you are headed toward a plateau 20 m high. If angle of elevation to the top is 10°, how far are you from the base o

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3 years ago

Determine the values of the constants r and s such that i(x, y) = x rys is an integrating factor for the given differential equa

garri49 [273]

$\underbrace{y(7xy^2+6)}_{M(x,y)}\,\mathrm dx+\underbrace{x(xy^2-1)}_{N(x,y)}\,\mathrm dy=0$

For the ODE to be exact, we require that $M_y=N_x$ , which we'll verify is not the case here.

$M_y=21xy^2+6$
$N_x=2xy^2-1$

So we distribute an integrating factor $i(x,y)$ across both sides of the ODE to get

$iM\,\mathrm dx+iN\,\mathrm dy=0$

Now for the ODE to be exact, we require $(iM)_y=(iN)_x$ , which in turn means

$i_yM+iM_y=i_xN+iN_x\implies i(M_y-N_x)=i_xN-i_yM$

Suppose $i(x,y)=x^ry^s$ . Then substituting everything into the PDE above, we have

$x^ry^s(19xy^2+7)=rx^{r-1}y^s(x^2y^2-x)-sx^ry^{s-1}(7xy^3+6y)$
$19x^{r+1}y^{s+2}+7x^ry^s=rx^{r+1}y^{s+2}-rx^ry^s-7sx^{r+1}y^{s+2}-6sx^ry^s$
$19x^{r+1}y^{s+2}+7x^ry^s=(r-7s)x^{r+1}y^{s+2}-(r+6s)x^ry^s$
$\implies\begin{cases}r-7s=19\\r+6s=-7\end{cases}\implies r=5,s=-2$

so that our integrating factor is $i(x,y)=x^5y^{-2}$ . Our ODE is now

$(7x^6y+6x^5y^{-1})\,\mathrm dx+(x^7-x^6y^{-2})\,\mathrm dy=0$

Renaming $M(x,y)$ and $N(x,y)$ to our current coefficients, we end up with partial derivatives

$M_y=7x^6-6x^5y^{-2}$
$N_x=7x^6-6x^5y^{-2}$

as desired, so our new ODE is indeed exact.

Next, we're looking for a solution of the form $\Psi(x,y)=C$ . By the chain rule, we have

$\Psi_x=7x^6y+6x^5y^{-1}\implies\Psi=x^7y+x^6y^{-1}+f(y)$

Differentiating with respect to $y$ yields

$\Psi_y=x^7-x^6y^{-2}=x^7-x^6y^{-2}+\dfrac{\mathrm df}{\mathrm dy}$
$\implies\dfrac{\mathrm df}{\mathrm dy}=0\implies f(y)=C$

Thus the solution to the ODE is

$\Psi(x,y)=x^7y+x^6y^{-1}=C$

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3 years ago

Find the area of the shaded figure.

olasank [31]

Answer:

8500 ft²

Step-by-step explanation:

First we need to find the area of the non shaded region within this shaded region. To find the area of this non shaded rectangle, use the formula base×height.

20×100=2000 ft².

Now we need to find the height and width of the shaded region which is,

25+25+20=70 Height

25+25+100=150 Width

mutiply these numbers 150×70=10500 ft²

Now we just need to subtract that inside area.

10500-2000=8500 ft²

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3 years ago