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julsineya [31]
1 year ago
9

Why is the classification species not considered a group? (1 point)

Chemistry
1 answer:
vitfil [10]1 year ago
6 0

Each species is a separate type of organism.

  • A species is a group of creatures that share similar traits. The same species of organisms are capable of sexual reproduction as well as interbreeding and producing fertile offspring. It is a fundamental unit of taxonomy and classification.
  • The system is divided into seven categories: Kingdom, Phylum or Division, Class, Order, Family, Genus, and Species. Kingdom is the most inclusive category.
  • In a group, many types of an organism can be included even if they do not share the same traits. But species is a group of organisms that share similar traits.
  • For example, human beings are species as they are all alike in physical features, way of reproduction, etc. But the animal is considered a group because it included a variety of living beings.

Therefore, Each species is not considered a group.

Learn more about taxonomy here:

brainly.com/question/1304906

#SPJ9

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A 25.0g sample of brass, which has a specific heat capacity of 0.375·J·g−1°C−1, is dropped into an insulated container containin
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Answer:

The equilibrium temperature of water is 25.6 °C

Explanation:

Step 1: Data given

Mass of the sample of brass = 25.0 grams

The specific heat capacity = 0.375 J/g°C

Mass of water = 250.0 grams

Temperature of water = 25.0 °C

The initial temperature of the brass is 96.7°C

Step 2: Calculate the equilibrium temperature

Heat lost = heat gained

Q(sample) = -Q(water)

Q = m*C* ΔT

m(sample)*c(sample)*ΔT(sample) = - m(water)*c(water)*ΔT(water)

⇒m(sample) = the mass of the sample of brass = 25.0 grams

⇒with c(sample) =The specific heat capacity = 0.375 J/g°C  

⇒with ΔT = the change of temperature = T2 - T1 =T2 - 96.7 °C

⇒with m(water) = the mass of the water = 250.0 grams

⇒with c(water) = the specific heat capacity = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = T2 - 25.0°C

25.0 * 0.375 * (T2 - 96.7) = - 250.0 * 4.184 J/g°C * (T2 - 25.0°C)

9.375T2 - 906.56 = -1046T2 + 26150

9.375T2 + 1046T2 = 26150 + 906.56

1055.375T2 = 27056.26

T2 = 25.6 °C

The equilibrium temperature of water is 25.6 °C

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Carbohydrates,Monosaccharides,and disaccharides

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