Answer:
Zn =⇒ Zn+2(0.10) + 2e- (anode)
Zn+2(?M) + 2e- === Zn(s) (cathode)
Zn + Zn+2(?M) ===⇒ Zn+2(0.10) + Zn
E = E^o -0.0592 log Q; in this case E^o is zero.
E = - 0.0592 /n logQ where n is the number of electrons transferred, in this
case n = 2
23 mV x 1 volt/1000mv = 0.023 Volts
0.023 = -0.0592 / 2 log(0.10) / [Zn+2]
0.023 = -0.0296 { log 0.10 – log [Zn+2] }
0.023 = -0.0296{ -1 - log[Zn+2] }
0.023 = +0.0296 + 0.0296log[Zn+2]
-0.0066 = 0.0296log[Zn+2]
-0.22= log[Zn+2]
[Zn+2] = 10^-0.22 = 0.603 Molar
Answer:
2.01% to the nearest hundredth.
Explanation:
Percent error =[ (8.96-8.78) / 8.96]* 100
= 0.020089 * 100
= 2.0089 %
Hello! Let me try to answer this :)
Thanks and please correct if there are any mistakes ^ ^
Answer:
ΔT = 76.5 °C
Explanation:
Given data:
Amount of water = 100.0 g
Energy needed = 32000 J
Change in temperature = ?
Solution,
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values in formula.
Q = m.c. ΔT
ΔT = Q / m.c
ΔT = 32000 j/ 100.0 g × 4.184 j/g. °C
ΔT = 32000 j / 418.4 j /°C
ΔT = 76.5 °C
