After careful consideration your answer is...
Leucippus and Democritus
*Hope I helped*
~Alanna~
Answer: they all relate to eachother
Explanation: every star every planet every sun its hard to belive they relate
to eachother but only becuase there in the same UNIVERSE
Answer:
<h2>Speed = 5.107 mile/hr</h2>
Explanation:
<h3>Given:</h3>
<u>distance</u> =50m = 0.0311 mile
<u>Time</u>= 21.93 seconds/3600 =0.00609 hour
<u>Speed</u><u>=</u>?
<h3>
Speed= Distance / Time </h3><h3>
= 0.0311 / 0.00609</h3><h3>
= 5.107 mile/hr</h3>
Answer:
CH₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 1 g
Mass of CO₂ = 3.14 g
Mass of H₂O = 1.29 g
Empirical formula =?
Next, we shall determine the mass of Carbon and hydrogen present in the compound. This can be obtained as follow:
For Carbon, C:
Mass of CO₂ = 3.14 g
Molar mass of CO₂ = 12 + (2×16)
= 12 + 32
= 44 g/mol
Molar mass of C = 12 g/mol
Mass of C =?
Mass of C = molar mass of C/ Molar mass of CO₂ × Mass of CO₂
Mass of C = 12/44 × 3.14
Mass of C = 0.86 g
For hydrogen, H:
Mass of C = 0.86 g
Mass of compound = 1 g
Mass of H =?
Mass of H = (Mass of compound) – (mass of C)
Mass of H = 1 – 0.86
Mass of H = 0.14 g
Finally, we shall determine the empirical formula of the cyclopropane. This can be obtained as follow:
Mass of C = 0.86 g
Mass of H = 0.14 g
Divide by their molar mass
C = 0.86 / 12 = 0.07
H = 0.14 / 1 = 0.14
Divide by the smallest
C = 0.07 / 0.07 = 1
H = 0.14 / 0.07 = 2
Thus, the empirical formula of cyclopropane is CH₂
1 mole ------------- 22.4 L ( at STP)
?? moles --------- 5.58 L
5.58 x 1 / 22.4 => 0.249 moles of N₂
