Answer:
144 g
Explanation:
Use the mole ratio of 4 mol CO2 for every 9 mol O2 to convert from mol O2 to mol CO2. Then use the molar mass of CO2 to convert from mol of CO2 to grams of CO2.
7.34 mol O2 • (4 mol CO2 / 9 mol O2) • (44.01 g CO2 / 1 mol CO2) = 144 g CO2
Answer:
A. CuCN
B. Sr(OCl)2
C. HBrO4
D. HI
E. Na2NH4PO4
F. KH2PO4
G. IF7
H. P4S10
I. HgO
J. Hg2I2
K. SeF6
Explanation:
All have different valent cation and anions like mono di and poly valent ions
We calculate for the amount of chromium metal in the reactant by,
= 350 x (mass of Cr2/mass of Cr2O3)
= 350 x (104/152)
= 239.47 grams
The amount of Cr metal in the product is only 213.2 grams. Thus, the percent yield.
percent yield = (213.2 grams/239.47) x 100%
= 89%
The correct answer is c
No because the amount of light absorbed
