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3 years ago

A certain orbital of the hydrogen atom has n = 4 and l = 2 what are the possible values of ml for this orbital?

1 answer:

3 0

The ml is also called as the magnetic quantum number. The value of ml can range from –l to +l including zero. Hence all of the possible values for ml given that l = 2 are:

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You have forgotten the ideal gas constant. Describe an experiment, similar to this one, that would allow you to determine the va

Gelneren [198K]

Information would you need to know about the H₂O₂ solution is through stoichiometry experiment

The ideal gas constant R can be found experimentally by determining the number of moles of gas that occupies a particular measured volume at a known pressure and temprature and the H₂O₂ is a chemical compound used un various chemical reactions and is slightly viscous than water and the experiment by decomposition of hydrogen peroxide and using the ideal gas law rearrangement equation we can calculate the value of r and we will need the information such as concentration, volume and moles of H₂O₂ to determine its stoichiometry

Know more about ideal gas constant

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5 0

1 year ago

A fluid occupying has a mass of 4mg. Calculate its density and specific volume in SI, EE, and BG units.

kondaur [170]

The question is incomplete, complete question is:

A fluid occupying $3.2 m^3$ of volume has a mass of 4 Mg. Calculate its density and specific volume in SI, EE, and BG units.

Explanation:

1) Mass of liquid = m = 4 Mg = 4 × 1,000 kg = 4,000 kg

(1 Mg = 1000 kg)

Volume of the fluid = V = $3.2 m^3$

Density of the fluid = D

$D=\frac{m}{V}=\frac{4,000 kg}{3.2 m^3}=1,250 kg/m^3$

Specific volume is the reciprocal of the density :

$V_{specific}=\frac{1}{Density}$

Specific volume of the fluid = $S_v$

$S_v=\frac{1}{D}=\frac{1}{1,250 kg/m^3}=0.0008 m^3/kg$

Density of the fluid in English Engineering units = D $(lb/ft^3)$

1 kg = 2.20462 lb

1 m = 3.280 ft

$D=\frac[1,250\times 2.20462 lb}{(3.280 ft)^3=78.95 lb/ft^3$

Specific volume of the fluid :

$=\frac{1}{78.95 lb/ft^3}=0.0127 ft^3/lb$

Density of the fluid in British Gravitational System units = D $(slug/ft^3)$

1 kg = 0.06852 slug

1 m = 3.280 ft

$D=\frac[1,250\times 0.0685218 slug}{(3.280 ft)^3=2.43 slug/ft^3$

Specific volume of the fluid :

$=\frac{1}{2.43 slug/ft^3}=0.412 ft^3/slug$

7 0

2 years ago

You have 345 mL of a 2.5 M NaCl solution. If you boil the water until the volume of the solution is 250 mLwhat will the molarity

HACTEHA [7]

The molarity of the solution will be 3.45 M

<h3>Further explanation </h3>

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution

V₁ = volume of the solution before dilution

M₂ = Molarity of the solution after dilution

V₂ = Molarity volume of the solution after dilution

The initial solution

345 mL of a 2.5 M NaCl solution.

M₁=2.5 M

V₁=345 ml

The solution after boiled :

V₂=250 ml

$\tt M_2=\dfrac{M_1.V_1}{V_2}\\\\M_2=\dfrac{2.5\times 345}{250}\\\\M_2=3.45~M$

5 0

2 years ago

Check out the list of scientific names. These names all represent animals. These are all animals but they cannot reproduce to pr

Dimas [21]

Answer:

Explanation:

they are not the same animal

7 0

2 years ago

Lead (II) chloride (PbCl2) has a Ksp of 1.17 x 10-5. Calculate the molar solubility of PbCl2, in moles per liter. Enter your ans

bixtya [17]

Answer:

1.43 * 10^-2

Explanation:

Firstly, we need to get the ionization equation for lead I chloride. We can then get the Initial, change and equilibrium table of the lead and chloride ions that can help us calculate the molar solubility. This is shown as follows:

PbCl2(s) --> Pb2+(aq) + 2 Cl-(aq)

This shows that one mole of lead ii chloride will yield 1 mole of the lead ion and 2 moles of the chloride ion.

The ICE table is shown below:

Pb2+ 2Cl-

Initial 0.00 0.00

Change +s +2s

Equilibrium s 2s

Ksp = [Pb2+][Cl-]^2

Ksp = [s][2s]^2

Ksp = 4s^3

s^3 = Ksp/4

s = cube.root [Ksp/4]

s = cube.root[1.17 * 10^-5/4]

s = 1.43 * 10^-2

3 0

2 years ago