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12345 [234]
3 years ago
10

Lithium, is used in dry cells and storage batteries and in high temperature lubricants, it has two naturally occurring isotopes,

6Li and 7Li. Calculate the atomic mass of lithium.
Chemistry
1 answer:
erastovalidia [21]3 years ago
7 0

<u>Answer:</u> The average atomic mass of lithium is 6.9241 u.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i ....(1)

  • <u>For _3^6\textrm{Li} isotope:</u>

Mass of _3^6\textrm{Li} isotope = 6 u

Percentage abundance of _3^6\textrm{Li} isotope = 7.59 %

Fractional abundance of _3^6\textrm{Li} isotope = 0.0759

  • <u>For _3^7\textrm{Li} isotope:</u>

Mass of _3^7\textrm{Li} isotope = 7 u

Percentage abundance of _3^7\textrm{Li} isotope = 92.41%

Fractional abundance of _3^7\textrm{Li} isotope = 0.9241

Putting values in equation 1, we get:

\text{Average atomic mass of Lithium}=[(6\times 0.0759)+(7\times 0.9241)]

\text{Average atomic mass of Lithium}=6.9241u

Hence, the average atomic mass of lithium is 6.9241 u.

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3 years ago
Calculate the maximum KE and velocity of an electron from zinc by a 275nm photon
Dmitry [639]

Answer:

Kinetic energy: 6.024*10^{-20}

Velocity: 3.64*10^{5}

Explanation:

From the equations of the photo-electric effect,

We know:

hv=hv_0+K.E

Where,

1.h is the Planck's constant which is 6.626*10^{-34}

2.v,v_0 are the frequency of light emitted and threshold frequencies respectively.

3.K.E is the kinetic energy of the electrons emitted.

By fact, we come to know that the threshold frequency of Zn is 300nm

And also v=\frac{c}{d}

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\frac{hc}{d}=\frac{hc}{d_0}+K.E\\K.E=\frac{hc}{d}-\frac{hc}{d_0}\\K.E=hc*(\frac{1}{d}-\frac{1}{d_0})\\K.E=6.626*10^{-34}*3*10^8*(\frac{1}{275*10^{-9}}-\frac{1}{300*10^{-9}})\\K.E=6.024*10^{-20}kgm^2s^{-2}

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K.E=\frac{1}{2}mv^2\\v^2=1.324*10^{11}\\v=3.64*10^5

8 0
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It helps creatures to walk on the water.

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Answer:

q = 38,5 kJ

Explanation:

In its melting point, at 0°C, water is liquid. The boiling point of water is 100°C. It is possible to estimate the heat you required to raise the temperature of water from 0°C to 100°C using:

q = C×m×ΔT

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Replacing:

q = 4,184J/g°C×92,0g×100°C

q = 38493 J, in kilojoules:

<em>q = 38,5 kJ</em>

<em></em>

I hope it helps!

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What was the primary cause of the increase in oxygen content between 400 and 300 million years ago

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