Question

What is the solution to the system of equations? 7z+3y=-11 2z+ 5y = 1

Answer 1

Answer:

y=1 , z=-2

Step-by-step explanation:

I will use the method of elimination :

Multiply the top equation by 5 to make equation 3 :

35z + 15y = -55

Multiply bottom equation by 3 to make equation 4:

6z + 15y = 3

Subtract equation 3 from equation 4 to eliminate the y :

-29z = 58

Divide both sides by -29 to solve for z :

z = 58 ÷ -29

z = -2

Substitute this value into either equation 1 or 2 to solve for y :  

I chose equation 2 :

2(-2) + 5y = 1

-4 + 5y = 1

Add 4 to both sides :

5y = 5

Divide both sides by 5 :  

y = 1

Hope this helped and have a good day