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fomenos
1 year ago
9

Why is helium found in deposits of uranium and thorium vores? What kind of radioactive emission produces it?

Chemistry
1 answer:
Drupady [299]1 year ago
4 0

Two protons and two neutrons are emitted and trapped as materials like uranium and thorium deep underground decay into radium and thorium, respectively. These alpha-particles transform into stable helium atoms as they take on electrons from their surroundings.

<h3>What elements go through alpha decay?</h3>

Alpha decay usually occurs in heavy nuclei such as uranium or plutonium, and therefore is a major part of the radioactive fallout from a nuclear explosion.

<h3>Where does alpha decay occur?</h3>

Alpha decay occurs most often in massive nuclei that have too large a proton to neutron ratio. An alpha particle, with its two protons and two neutrons, is a very stable configuration of particles.

Learn more about alpha decay here:

brainly.com/question/1898040

#SPJ4

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andre [41]

Answer: im not writting a pharaphraph. Buuuuuuuuuuuut... explian the type of reaction then explanie how that type of reaction works.

Explanation:

6 0
2 years ago
Read 2 more answers
A sample of gas has a volume of 4.4 liters when the pressure is 3.3 atm. What is the volume when the pressure is reduced to 2.2
murzikaleks [220]
6.6 liters would be your answer. 
5 0
3 years ago
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Uranium has atomic number 92. Its most common isotope is 238U, but the form used in nuclear bombs and nuclear power plants is 23
Yakvenalex [24]

Explanation:

Atomic Number = Number of protons

Mass Number = Number of protons + Number of neutrons

Isotopes are simply atoms of an element with the same number of protons and different number of neutrons.

First Isotope -- 238U

Number of neutrons = Mass Number - Atomic Number

Number of neutrons =  238 - 92 = 146

Second Isotope -- 235U

Number of neutrons = Mass Number - Atomic Number

Number of neutrons =  235 - 92 = 143

3 0
3 years ago
2. A 2.5 mol SAMPLE OF OXYGEN GAS (O2) INCREASES TO 3.2 mol
lana [24]

696.32 mmHg is the final pressure of the gas.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas.

Given data:

P_1 = 720 mmHg              

P_2 = ?

n_1 = 2.5 mol                

n_2 = 3.2 mol

V_1 = 34 L            

V_2 = 45 L

Formula

Combined gas law

\frac{P_1 V_1}{n_1}  = \frac{P_2 V_2}{n_2}

P_2 = 696.32 mmHg

Hence, 696.32 mmHg is the final pressure of the gas.

Learn more about an ideal gas equation here:

brainly.com/question/19251972

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6 0
2 years ago
What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?
sp2606 [1]
First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation. 

CH4 + 2O2 ---> CO2 + 2H20

Then using dimension analysis: 

4.60*10^{-3} g CH4 ( \frac{moleCH4}{16 g CH4}) * ( \frac{2mole O2}{mole CH4}) * ( \frac{32 g O2}{mole O2} ) =  0.0184 g O_{2}
7 0
3 years ago
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