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valentina_108 [34]
2 years ago
13

Write down a balanced chemical equation for a neutralizing reaction of a titration

Chemistry
1 answer:
vesna_86 [32]2 years ago
3 0

Balanced chemical equation for a neutralizing reaction:

NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l).

Neutralization is is reaction in which an acid and a base react quantitatively (same omount of substance) with each other.

pH of sodium hydroxide (NaOH) solution is above seven (basic), when solution of hydrochloric acid (HCl) is added, pH slowly dropping until it became neutral solution (pH is equal seven) and that is the endpoint of titration.

Chemist can draw pH curve (graph showing the change in pH of a solution, which is being titrated) for titration and determine an equivalence point.

More about neutralization: brainly.com/question/23008798

#SPJ4

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Answer:

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Explanation:

The distance covered by the wave in one second is equal to its wavelength, therefore,

wave velocity=wavelength/time period

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How can you tell the difference between a compound and a heterogeneous mixture?
skad [1K]

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If a substance can be separated into its elements, it is a compound. If a substance is not chemically pure, it is either a heterogeneous mixture or a homogeneous mixture. If its composition is uniform throughout, it is a homogeneous mixture.

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3 years ago
What is the molar solubility of AgCl in a 0.050 M NaCl solution? The Ksp of AgCl is 1.6 x 10-10. (Assume that the contribution o
Hitman42 [59]

The molar solubility of AgCl:

The molar solubility of AgCl in a 0.050 M NaCl solution is 8 x 10^{-8} M Ag^{+}

What is solubility?

The solubility is the quantity of reagent required to saturate the solution or bring about the dissociation reaction's equilibrium.

Reaction:

The dissociation reaction of AgCl in water is:

AgCl  ⇄ Ag^{+} + Cl^{-}

Each mole of AgCl that dissolves in this reaction yields 1 mole of both Ag^{+} and  Cl^{-}. The concentration of either the Ag or Cl ions would then be equal to the solubility.

Solubility= [Ag^{+}] = [Cl^{-}]

Calculation:

in 0.050 M NaCl, the [Cl^{-}] = 1 x 10^{-2}

ksp = [Ag^{+}] x [Cl^{-}]

1.6 x 10^{-10} = [Ag{+}] x ( 5 x 10^{-2})

[Ag^{+}] = 5 x 10^{+2} x 1.6 x 10^{-10}

[Ag^{+}] = 5 x 1.6 x 10^{-10+2}

[Ag^{+}] = 8 x 10^{-8} M

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