Answer:
maybe they don't want to answer it only if you give them a lot of points and brainliest they will answer it i think
Explanation:
From the calculations performed, the Kb of the reaction is 9.9 * 10^-10
<h3>What is Kb?</h3>
The term Kb refers to the base dissociation constant of a solution. We have the following information from the question;
pH of the solution = 8.60
concentration of p-toluidine = 0.016-M
Recall that pOH = 14 - pH
pOH = 14 - 8.60 = 5.4
[OH] = Antilog (-5.4) = 3.98 * 10^-6 M
We have to set up the ICE table;
CH3C6H4NH2(aq) + H2O(l) ⇄ CH3C6H4NH3^+(aq) + OH^-(aq)
I 0.016 0 0
C -x +x +x
E 0.016 - x 3.98 * 10^-6 3.98 * 10^-6
Hence;
Kb = [3.98 * 10^-6]^2/[0.016 - 3.98 * 10^-6]
Kb = 9.9 * 10^-10
Learn more about Kb: brainly.com/question/12726841
To calculate the partial pressure, we have to calulate the total pressure first.
Total pressure = (nRT/V)SO2 + (nRT/V)CO2
n is the number of moles
R is the general gas constant = 0.0821 L.atm/K.mole
T is the temperature in Kelvin
V is the total volume
n SO2 = mass/molar mass = 5/ 32 + 16*2 = 0.078125
n CO2 = mass/molar mass = 5/14+ 16*2 = 0.1
T = 50+273 = 323K
V = 750/1000 = 0.75 liters
Total Pressure = (0.078125*0.0821*323/0.75) + (0.1*0.0821*323/0.75) = 2.7623 + 3.535 = 6.298 atm
Partial pressure = x SO2 * Total Pressure = (no. of moles of SO2 / total no. of moles) * Total pressure = (0.078125/0.078125+0.1) * 6.298 = 2.762 atm.
What is this you got to do your school work you not homeschooled so your fault
The answer is 43.5 l of ideal gas will be produced
