To get the ∆S of the reaction, we simply have to add the ∆S of the reactants and the ∆S of the products. Then, we get the difference between the ∆S of the products and the ∆S of the products. If the <span>∆S is negative, then the reaction spontaneous. If the otherwise, the reaction is not spontaneous.</span>
<span>4 C3H5(NO3)3 = 12 CO2 + 6 N2 + 10 H2O + O<span>2
That's the answer lovely~</span></span>
Answer:
9 : 8
Explanation:
Aluminum oxide has the following formula Al₂O₃.
Next, we shall determine the mass of Al and O₂ in Al₂O₃. This can be obtained as follow:
Mass of Al in Al₂O₃ = 2 × 27 = 54 g
Mass of O₂ in Al₂O₃ = 3 × 16 = 48 g
Finally, we shall determine the mass ratio of Al and O₂. This can be obtained as follow:
Mass of Al = 54 g
Mass of O₂ = 48 g
Mass of Al : Mass of O₂ = 54 : 48
Mass of Al : Mass of O₂ = 54 / 48
Mass of Al : Mass of O₂ = 9 / 8
Mass of Al : Mass of O₂ = 9 : 8
Therefore, the mass ratio of Al and O₂ in Al₂O₃ is 9 : 8
Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.
Explanation:
Given: n = 2
The relation between energy and
orbit of an atom is as follows.
![E = - \frac{13.6}{n^{2}} eV](https://tex.z-dn.net/?f=E%20%3D%20-%20%5Cfrac%7B13.6%7D%7Bn%5E%7B2%7D%7D%20eV)
Substitute the values into above formula as follows.
![E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV](https://tex.z-dn.net/?f=E%20%3D%20-%20%5Cfrac%7B13.6%7D%7Bn%5E%7B2%7D%7D%20eV%5C%5C%3D%20-%20%5Cfrac%7B13.6%7D%7B%282%29%5E%7B2%7D%7D%5C%5C%3D%20-%203.40%20eV)
The negative sign indicates that energy is being released.
Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.
Answer:
The Supreme Court of Appeal
Explanation:
The Supreme Court of Appeal is based in Bloemfontein in the Free State. Except for the Constitutional Court, it is the highest court in South Africa and it only deals with cases sent to it from the High Court.