Problem 1
<h3>Answers:</h3><h3>angle 6 = 50</h3><h3>angle 7 = 50</h3><h3>angle 8 = 40</h3>
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Work Shown:
point E = intersection point of diagonals.
x = measure of angle 6
y = measure of angle 8
angle 7 is also x because triangle AED is isosceles (AE = ED)
Focus on triangle AED, the three angles A, E, D add to 180
A+E+D = 180
x+80+x = 180
2x+80 = 180
2x = 180-80
2x = 100
x = 100/2
x = 50
So both angles 6 and 7 are 50 degrees.
Turn to angle 8. This is adjacent to angle 7. The two angles form a 90 degree angle at point A. This is because a rectangle has 4 right angles.
(angle7)+(angle8) = 90
50+y = 90
y = 90-50
y = 40
angle 8 = 40 degrees
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Problem 2
<h3>Answers:</h3><h3>angle 2 = 61</h3><h3>angle 3 = 61</h3>
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Work Shown:
Angle 5 is 29 degrees (given). So is angle 4 because these are the base angles of isosceles triangle DEC (segment DE = segment EC)
angle 3 and angle 4 form a 90 degree angle
x = measure of angle 3
(angle 3)+(angle 4) = 90
x+29 = 90
x = 90-29
x = 61
Angle 2 is congruent to angle 3 since triangle BEC is isosceles (BE = EC), so both angle 2 and angle 3 are 61 degrees each.
Answer:
a straight line from the center to the circumference of a circle .
Step-by-step explanation:
please give brainliest
Hi there! The answer is y = -3x - 21
Let's set up the equation of the line step by step! First we need to know that we need to set up an equation in slope-intercept form. We get the following:
y = ax + b.
a represents the slope of the line.
b represents the intercept with the y-axis.
Since our new line is parallel to y = -3x + 1, both lines have the same slope. Therefore the slope of our line, which is represented by a, is -3.
y = -3x + b.
We also know that this line goes through the point (-5, -6) and therefore we can plug in these coordinates into our formula.
-6 = -3 × -5 + b
Simplify
-6 = 15 + b
Subtract 15
-21 = b
Switch sides
b = -21
Hence, y = -3x - 21
~ Hope this helps you!
<h2>
Explanation:</h2><h2>
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An irrational number is a number that can't be written as a simple fraction while a rational number is a number that can be written as the ratio of two integers, that is, as a simple fraction. So in this case we have the number 2 which is ration, and we can multiply it by an irrational number 
such that the product is an irrational number. So any irrational number will meet our requirement because the product of any rational number and an irrational number will lead to an irrational number. For instance:
